{"id":23230,"date":"2022-11-24T18:18:09","date_gmt":"2022-11-24T12:48:09","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-compare-a-nested-list-of-dicts-to-another-nested-list-of-dicts-and-update-the-values-in-one-from-the-other\/"},"modified":"2022-11-24T18:18:09","modified_gmt":"2022-11-24T12:48:09","slug":"solved-how-to-compare-a-nested-list-of-dicts-to-another-nested-list-of-dicts-and-update-the-values-in-one-from-the-other","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-compare-a-nested-list-of-dicts-to-another-nested-list-of-dicts-and-update-the-values-in-one-from-the-other\/","title":{"rendered":"[Solved] How to compare a nested list of Dicts to another nested list of Dicts and update the values in one from the other"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-56239468\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"56239468\" data-parentid=\"56227511\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>I may have been massively over complicating things here, this appears to do what I want (ignoring the insertion of completely new markets \/ selection_id&#8217;s for now):<\/p>\n<pre><code>new_order_list = []\n\nfor x in updated_orders:\n    for y in x['Live_orders']:\n        orders_to_update = {}\n        orders_to_update.update({'Market_id': x['Market_id'],\n                                'Selection_id': y['selection_id'],\n                                'live_orders': y['live_orders']})\n        new_order_list.append(orders_to_update)\n\nfor z in new_order_list:\n    for a in original_state:\n        for b in a['position_list']:\n                if z['Market_id'] == b['Market_id'] and z['Selection_id'] == b['Selection_id']:\n                    #for c in b['Orders']:\n                    print(b['Market_id'], b['Selection_id'], z['live_orders'])\n                    b.update({'Orders': z['live_orders']})\n<\/code><\/pre>\n<p>I must have missed the obvious solution and was looking for something far too complex, but hopefully this will help someone else as this must be a fairly common problem (yet with very few posts on the solution)!<\/p>\n<p>Here is how I tackled the updates where the orders were not in the <code>original_state<\/code>:<\/p>\n<pre><code>uo_list = []\n\nfor i in updated_orders:\n    uo_list.append(i['Market_id'])\n\nos_list = []\n\nfor j in original_state:\n    os_list.append(j['Market_id'])\n\nnew_list = list(set(uo_list).difference(os_list))\n\nfor i in updated_orders:\n    for j in new_list:\n        if i['Market_id'] == j:\n            print('Append this as required', i)\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved How to compare a nested list of Dicts to another nested list of Dicts and update the values in one from the other <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] I may have been massively over complicating things here, this appears to do what I want (ignoring the insertion of completely new markets \/ selection_id&#8217;s for now): new_order_list = [] for x in updated_orders: for y in x[&#8216;Live_orders&#8217;]: orders_to_update = {} orders_to_update.update({&#8216;Market_id&#8217;: x[&#8216;Market_id&#8217;], &#8216;Selection_id&#8217;: y[&#8216;selection_id&#8217;], &#8216;live_orders&#8217;: y[&#8216;live_orders&#8217;]}) new_order_list.append(orders_to_update) for z in new_order_list: for a &#8230; <a title=\"[Solved] How to compare a nested list of Dicts to another nested list of Dicts and update the values in one from the other\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-compare-a-nested-list-of-dicts-to-another-nested-list-of-dicts-and-update-the-values-in-one-from-the-other\/\" aria-label=\"More on [Solved] How to compare a nested list of Dicts to another nested list of Dicts and update the values in one from the other\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[834,540,431,349],"class_list":["post-23230","post","type-post","status-publish","format-standard","hentry","category-solved","tag-dictionary","tag-list","tag-nested","tag-python"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] How to compare a nested list of Dicts to another nested list of Dicts and update the values in one from the other - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-compare-a-nested-list-of-dicts-to-another-nested-list-of-dicts-and-update-the-values-in-one-from-the-other\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to compare a nested list of Dicts to another nested list of Dicts and update the values in one from the other - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] I may have been massively over complicating things here, this appears to do what I want (ignoring the insertion of completely new markets \/ selection_id&#8217;s for now): new_order_list = [] for x in updated_orders: for y in x[&#039;Live_orders&#039;]: orders_to_update = {} orders_to_update.update({&#039;Market_id&#039;: x[&#039;Market_id&#039;], &#039;Selection_id&#039;: y[&#039;selection_id&#039;], &#039;live_orders&#039;: y[&#039;live_orders&#039;]}) new_order_list.append(orders_to_update) for z in new_order_list: for a ... 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