{"id":21239,"date":"2022-11-12T17:14:07","date_gmt":"2022-11-12T11:44:07","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-force-java-to-print-out-large-numbers-without-the-use-of-long-or-double-duplicate\/"},"modified":"2022-11-12T17:14:07","modified_gmt":"2022-11-12T11:44:07","slug":"solved-how-to-force-java-to-print-out-large-numbers-without-the-use-of-long-or-double-duplicate","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-force-java-to-print-out-large-numbers-without-the-use-of-long-or-double-duplicate\/","title":{"rendered":"[Solved] How to Force Java to Print out Large Numbers without the use of Long or Double? [duplicate]"},"content":{"rendered":"

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I tried using the long type, but unfortunately, that didn’t work<\/p>\n<\/blockquote>\n

long finalP = startingP * growthR;\n<\/code><\/pre>\n
As long as startingP<\/code> and growthR<\/code> are still int<\/code>, this calculation will still be done using 32 bit integers (and only converted to 64 bit integers afterwards, when you already encountered overflow).<\/p>\n
You can change all your variables to long<\/code>. Then you will be able to work with larger numbers, but eventually those will also overflow.<\/p>\n
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Is there a way for Java to print a large number without entering the negatives and ultimately the 0s<\/p>\n<\/blockquote>\n
Depending on your application needs, you may need to look at either infinite-precision BigInteger<\/code> or floating point numbers such as double<\/code> (which can represent much larger quantities, but with a loss of precision in the lower digits — that seems acceptable here).<\/p>\n<\/p><\/div>\n
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            4<\/span> <\/p><\/div>\n<\/div>\n
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solved How to Force Java to Print out Large Numbers without the use of Long or Double? [duplicate] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] I tried using the long type, but unfortunately, that didn’t work long finalP = startingP * growthR; As long as startingP and growthR are still int, this calculation will still be done using 32 bit integers (and only converted to 64 bit integers afterwards, when you already encountered overflow). You can change all your … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[323],"class_list":["post-21239","post","type-post","status-publish","format-standard","hentry","category-solved","tag-java"],"yoast_head":"\n[Solved] How to Force Java to Print out Large Numbers without the use of Long or Double? [duplicate] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-force-java-to-print-out-large-numbers-without-the-use-of-long-or-double-duplicate\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to Force Java to Print out Large Numbers without the use of Long or Double? [duplicate] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] I tried using the long type, but unfortunately, that didn’t work long finalP = startingP * growthR; As long as startingP and growthR are still int, this calculation will still be done using 32 bit integers (and only converted to 64 bit integers afterwards, when you already encountered overflow). You can change all your ... 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