{"id":21204,"date":"2022-11-12T14:10:36","date_gmt":"2022-11-12T08:40:36","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-javascript-find-lowest-value-in-array-of-objects\/"},"modified":"2022-11-12T14:10:36","modified_gmt":"2022-11-12T08:40:36","slug":"solved-javascript-find-lowest-value-in-array-of-objects","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-javascript-find-lowest-value-in-array-of-objects\/","title":{"rendered":"[Solved] JavaScript, find lowest value in array of objects"},"content":{"rendered":"

[ad_1]
\n<\/p>\n

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You have 2 options: <\/p>\n

    \n
  1. \n

    the faster one- a simple loop where you always keep the lowest one you found so far: <\/p>\n

    let lowest = arr[0];\nfor(let i=1; i<0; i++)\n{\n    if(arr[i] < lowest) \/\/ I used < for the example, enter your comparison logic here\n     lowest = arr[i];\n}\n<\/code><\/pre>\n<\/li>\n
  2. \n
    The less efficient way, but might help you later in your code: sorting the array using ‘Array.sort’<\/a> method: <\/p>\n
    array.sort( (el1, el2) => {\n  if(el1 > el2) \/\/ again- I used > sign, put the actual comparison logic here, i.g: el1.coordinateid[0] > el2.coordinateid[0] and so on\n    return -1;\n  else return 1;\n});\n<\/code><\/pre>\n<\/li>\n<\/ol>\n
    Note that the sort array work like that: you give it a callback function which gets 2 elements of the array. If you return -1 it means the first element that passed should come before<\/em> the 2nd element when they are put back in the sorted array, 0 means they’re equal and 1 means that the 2nd element passed to the function should come first.
    \nSee the sort<\/code> method link above for more explanation.<\/p>\n<\/p><\/div>\n
    <\/div>\n<\/div>\n
                0<\/span> <\/p><\/div>\n<\/div>\n
    [ad_2]<\/p>\n
    solved JavaScript, find lowest value in array of objects <\/p>\n","protected":false},"excerpt":{"rendered":"
    [ad_1] You have 2 options: the faster one- a simple loop where you always keep the lowest one you found so far: let lowest = arr[0]; for(let i=1; i<0; i++) { if(arr[i] < lowest) \/\/ I used < for the example, enter your comparison logic here lowest = arr[i]; } The less efficient way, but … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[4876,4875],"class_list":["post-21204","post","type-post","status-publish","format-standard","hentry","category-solved","tag-deck-gl","tag-google-data-studio"],"yoast_head":"\n[Solved] JavaScript, find lowest value in array of objects - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-javascript-find-lowest-value-in-array-of-objects\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] JavaScript, find lowest value in array of objects - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You have 2 options: the faster one- a simple loop where you always keep the lowest one you found so far: let lowest = arr[0]; for(let i=1; i<0; i++) { if(arr[i] < lowest) \/\/ I used < for the example, enter your comparison logic here lowest = arr[i]; } The less efficient way, but ... 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