{"id":21094,"date":"2022-11-12T03:03:38","date_gmt":"2022-11-11T21:33:38","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-while-trying-to-print-the-address-of-a1-error-lvalue-required-as-unary-operand-pops-up\/"},"modified":"2022-11-12T03:03:38","modified_gmt":"2022-11-11T21:33:38","slug":"solved-while-trying-to-print-the-address-of-a1-error-lvalue-required-as-unary-operand-pops-up","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-while-trying-to-print-the-address-of-a1-error-lvalue-required-as-unary-operand-pops-up\/","title":{"rendered":"[Solved] while trying to print the address of a[1] error: lvalue required as unary ‘&’ operand pops up"},"content":{"rendered":"

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For any array or pointer a<\/code> and index i<\/code>, the expression a[i]<\/code> is exactly<\/em> equal to *(a + i)<\/code>. From that we can draw the conclusion that a + i<\/code> is a pointer which is equal to &a[i]<\/code>.<\/p>\n

So when you try to do &(a + 1)<\/code> that’s really equal to &&a[1]<\/code> which makes no sense and gives you an error.<\/p>\n<\/p><\/div>\n

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<\/span> <\/p><\/div>\n<\/div>\n

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solved while trying to print the address of a[1] error: lvalue required as unary ‘&’ operand pops up <\/p>\n","protected":false},"excerpt":{"rendered":"

[ad_1] For any array or pointer a and index i, the expression a[i] is exactly equal to *(a + i). From that we can draw the conclusion that a + i is a pointer which is equal to &a[i]. So when you try to do &(a + 1) that’s really equal to &&a[1] which makes … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324,1740],"class_list":["post-21094","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c","tag-c14"],"yoast_head":"\n[Solved] while trying to print the address of a[1] error: lvalue required as unary '&' operand pops up - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-while-trying-to-print-the-address-of-a1-error-lvalue-required-as-unary-operand-pops-up\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] while trying to print the address of a[1] error: lvalue required as unary '&' operand pops up - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] For any array or pointer a and index i, the expression a[i] is exactly equal to *(a + i). From that we can draw the conclusion that a + i is a pointer which is equal to &a[i]. So when you try to do &(a + 1) that’s really equal to &&a[1] which makes ... 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