{"id":20419,"date":"2022-11-09T16:01:48","date_gmt":"2022-11-09T10:31:48","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-java-program-to-find-a-pallindrome-closed\/"},"modified":"2022-11-09T16:01:48","modified_gmt":"2022-11-09T10:31:48","slug":"solved-java-program-to-find-a-pallindrome-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-java-program-to-find-a-pallindrome-closed\/","title":{"rendered":"[Solved] Java program to find a pallindrome [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-39513470\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"39513470\" data-parentid=\"39513412\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<pre><code>boolean isPalindrome(String input) {\n    for (int i=0; i &lt; input.length() \/ 2; ++i) {\n        if (input.charAt(i) != input.charAt(input.length() - i - 1)) {\n            return false;\n        }\n    }\n\n    return true;\n}\n<\/code><\/pre>\n<p>This solution is self explanatory, the only edge case requiring explanation is what happens for words with an odd number of letters.  For an input containing an odd number of letters, the middle element will not be touched by the loop, which is OK because it has no effect on whether the input is a palindrome.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">0<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Java program to find a pallindrome [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] boolean isPalindrome(String input) { for (int i=0; i &lt; input.length() \/ 2; ++i) { if (input.charAt(i) != input.charAt(input.length() &#8211; i &#8211; 1)) { return false; } } return true; } This solution is self explanatory, the only edge case requiring explanation is what happens for words with an odd number of letters. For an &#8230; <a title=\"[Solved] Java program to find a pallindrome [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-java-program-to-find-a-pallindrome-closed\/\" aria-label=\"More on [Solved] Java program to find a pallindrome [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[1957,323],"class_list":["post-20419","post","type-post","status-publish","format-standard","hentry","category-solved","tag-bluej","tag-java"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>[Solved] Java program to find a pallindrome [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-java-program-to-find-a-pallindrome-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Java program to find a pallindrome [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] boolean isPalindrome(String input) { for (int i=0; i &lt; input.length() \/ 2; ++i) { if (input.charAt(i) != input.charAt(input.length() - i - 1)) { return false; } } return true; } This solution is self explanatory, the only edge case requiring explanation is what happens for words with an odd number of letters. For an ... 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