{"id":20315,"date":"2022-11-09T08:43:44","date_gmt":"2022-11-09T03:13:44","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-print-a-diamond-shape-composed-of-letters-closed\/"},"modified":"2022-11-09T08:43:44","modified_gmt":"2022-11-09T03:13:44","slug":"solved-how-to-print-a-diamond-shape-composed-of-letters-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-print-a-diamond-shape-composed-of-letters-closed\/","title":{"rendered":"[Solved] How to print a diamond shape composed of letters? [closed]"},"content":{"rendered":"

[ad_1]
\n<\/p>\n

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Try this. Tested working.<\/p>\n

using System;\n\nnamespace ConsoleApplication\n{\n    internal class Program\n    {\n        private static void Main(string[] args)\n        {\n            char[] letter = new char[26]\n            {\n                'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U',\n                'V', 'W', 'X', 'Y', 'Z'\n            };\n            int letter_number = 0;\n\n            \/\/array of strings\n            string[] diamond = new string[52];\n            \/\/get the letter\n            Console.WriteLine(\"User enters a Letter between A and Z \");\n            char user_letter = Console.ReadKey().KeyChar;\n            Console.WriteLine(\"\");\n            \/\/search for letter number in the array letter\n            for (int i = 0; i < letter.Length; i++)\n            {\n                if (letter[i] == user_letter)\n                {\n                    letter_number = i;\n                    break;\n                }\n            }\n\n            \/\/construct diamond \n\n            for (int i = 0; i <= letter_number; i++)\n            {\n                \/\/add initial spaces\n                for (int j = 0; j < letter_number - i; j++)\n                {\n                    diamond[i] += \" \";\n                }\n\n                \/\/add letter (first time)\n                diamond[i] += letter[i];\n\n                \/\/add space between letters\n                if (letter[i] != 'A')\n                {\n                    for (int j = 0; j < 2*i - 1; j++)\n                    {\n                        diamond[i] += \" \";\n                    }\n                    \/\/add letter (second time)\n                    diamond[i] += letter[i];\n                }\n                \/\/ Draw the first part of the diamond as it's composing.\n                Console.WriteLine(diamond[i]);\n            }\n\n            for (int i = letter_number - 1; i >= 0; i--)\n            {\n                \/\/ Draw the second part of the diamond\n                \/\/ Writing the diamondArray in reverse order.\n                Console.WriteLine(diamond[i]);\n            }\n\n            \/\/ Mark a pause\n            Console.ReadKey();\n        }\n    }\n}\n<\/code><\/pre>\n
Output : <\/p>\n
User enters a Letter between A and Z\nK\n          A\n         B B\n        C   C\n       D     D\n      E       E\n     F         F\n    G           G\n   H             H\n  I               I\n J                 J\nK                   K\n J                 J\n  I               I\n   H             H\n    G           G\n     F         F\n      E       E\n       D     D\n        C   C\n         B B\n          A\n<\/code><\/pre>\n<\/p><\/div>\n
<\/div>\n<\/div>\n
            5<\/span> <\/p><\/div>\n<\/div>\n
[ad_2]<\/p>\n
solved How to print a diamond shape composed of letters? [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Try this. Tested working. using System; namespace ConsoleApplication { internal class Program { private static void Main(string[] args) { char[] letter = new char[26] { ‘A’, ‘B’, ‘C’, ‘D’, ‘E’, ‘F’, ‘G’, ‘H’, ‘I’, ‘J’, ‘K’, ‘L’, ‘M’, ‘N’, ‘O’, ‘P’, ‘Q’, ‘R’, ‘S’, ‘T’, ‘U’, ‘V’, ‘W’, ‘X’, ‘Y’, ‘Z’ }; int letter_number … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324],"class_list":["post-20315","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c"],"yoast_head":"\n[Solved] How to print a diamond shape composed of letters? [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-print-a-diamond-shape-composed-of-letters-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to print a diamond shape composed of letters? [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Try this. Tested working. using System; namespace ConsoleApplication { internal class Program { private static void Main(string[] args) { char[] letter = new char[26] { 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z' }; int letter_number ... 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