{"id":19411,"date":"2022-11-06T14:57:32","date_gmt":"2022-11-06T09:27:32","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-select-top-1-from-each-group-sql\/"},"modified":"2022-11-06T14:57:32","modified_gmt":"2022-11-06T09:27:32","slug":"solved-select-top-1-from-each-group-sql","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-select-top-1-from-each-group-sql\/","title":{"rendered":"[Solved] Select top 1 from each group sql"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-20883633\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"20883633\" data-parentid=\"20883539\" data-score=\"2\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Maybe this&#8230;  get the maximum sum for each city and menu item name.  Top returns 1 row not one row per group.  you need to use the max aggregate to make this work the way you want.<\/p>\n<p>you can&#8217;t double aggregate max(sum(Quantity)) so you have to either use a sub select, or use a CTE (common table expression).  This is the subselect.<\/p>\n<pre><code>Select city, itemName, max(Quantity)\nFROM (\n            SELECT \n                    l.city AS City,\n                    mi.name AS ItemName,\n                    SUM(ft.quantity_sold) AS Quantity\n            FROM\n                    FactTable ft\n                            JOIN MenuItem mi ON (ft.menuItemID = mi.ID)\n                            JOIN Location l ON (ft.locationID = l.ID)\n            GROUP BY\n                    l.city, mi.name) sub\nGROUP BY City, ItemName;\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">0<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Select top 1 from each group sql <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Maybe this&#8230; get the maximum sum for each city and menu item name. Top returns 1 row not one row per group. you need to use the max aggregate to make this work the way you want. you can&#8217;t double aggregate max(sum(Quantity)) so you have to either use a sub select, or use a &#8230; <a title=\"[Solved] Select top 1 from each group sql\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-select-top-1-from-each-group-sql\/\" aria-label=\"More on [Solved] Select top 1 from each group sql\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[341,500],"class_list":["post-19411","post","type-post","status-publish","format-standard","hentry","category-solved","tag-sql","tag-sql-server"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>[Solved] Select top 1 from each group sql - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-select-top-1-from-each-group-sql\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Select top 1 from each group sql - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Maybe this&#8230; get the maximum sum for each city and menu item name. Top returns 1 row not one row per group. you need to use the max aggregate to make this work the way you want. you can&#8217;t double aggregate max(sum(Quantity)) so you have to either use a sub select, or use a ... 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