{"id":18693,"date":"2022-11-01T16:18:01","date_gmt":"2022-11-01T10:48:01","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-pointers-and-char-in-c-closed\/"},"modified":"2022-11-01T16:18:01","modified_gmt":"2022-11-01T10:48:01","slug":"solved-pointers-and-char-in-c-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-pointers-and-char-in-c-closed\/","title":{"rendered":"[Solved] Pointers and char[] in C [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-52237044\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"52237044\" data-parentid=\"52236761\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>To know how all these three code blocks works, you got to start reading good <code>C<\/code> book specially array and pointers concept.<\/p>\n<p><strong>Case 1 :-<\/strong> In the below code block<\/p>\n<pre><code>int main(void) {\n    char x[] = \"gate2011\";\n    char *ptr = x;\n    printf (\"%s\", ptr+ptr[3]-ptr[1]);\n    return 0;\n}\n<\/code><\/pre>\n<p>It looks like<\/p>\n<pre><code> x[0]   x[1]   x[2]     x[3]   x[4]    x[5]     x[6]   x[7]    x[8]\n 0x100  0x101  0x102   0x103   ..                                   --&gt;(assume 0x100 is base address of x )\n ---------------------------------------------------------------------\n| g   |   a   |   t   |   e   |   2   |   0   |  1   |   1   |   \\0   |\n----------------------------------------------------------------------\nx\nptr (ptr = x, i.e ptr points to base address of x)\n<\/code><\/pre>\n<p>This<\/p>\n<pre><code>ptr+ptr[3]-ptr[1]) == 0x100 + ( 'e' - 'a' )\n                   == 0x100 +  4\n                   == 0x104\n<\/code><\/pre>\n<p>So when <code>printf()<\/code> executes it will start printing from <code>0x104<\/code> until <code>\\0<\/code>, hence it prints <code>2011<\/code>.<\/p>\n<p><strong>Case 2 :-<\/strong>  In the below code block<\/p>\n<pre><code>int main(void){\n        char x[] = \"sanguineapp\";\n        char *ptr = x;\n        printf (\"%s\", ptr+ptr[5]-ptr[2]);\n        return 0;\n}\n<\/code><\/pre>\n<p>It looks like<\/p>\n<pre><code>x[0]   x[1]   x[2]     x[3]   x[4]    x[5]     x[6]   x[7]    x[8] ..\n 0x100  0x101  0x102   0x103   ..                                   --&gt; (assume 0x100 is base address of x )\n ---------------------------------------------------------------------------------\n| s   |   a   |   n   |   g   |   u   |   i   |  n   |   e   |   a   |  p  | \\0  |\n---------------------------------------------------------------------------------\nx\nptr (ptr = x, i.e ptr points to base address of x)\n<\/code><\/pre>\n<p>This<\/p>\n<pre><code>ptr+ptr[5]-ptr[2] == 0x100 + ( 'i' - 'n' )\n                  == 0x100 + ( -5) \/* so it will try to access invalid memory i.e base address 5 *\/\n<\/code><\/pre>\n<p>So when <code>printf()<\/code> executes, since you are providing wrong address to <code>printf()<\/code>, o\/p of this statement causes <strong>undefined behavior<\/strong>, you are lucky that it didn&#8217;t crashes.<\/p>\n<p>Same happens in third case also.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Pointers and char[] in C [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] To know how all these three code blocks works, you got to start reading good C book specially array and pointers concept. Case 1 :- In the below code block int main(void) { char x[] = &#8220;gate2011&#8221;; char *ptr = x; printf (&#8220;%s&#8221;, ptr+ptr[3]-ptr[1]); return 0; } It looks like x[0] x[1] x[2] x[3] &#8230; <a title=\"[Solved] Pointers and char[] in C [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-pointers-and-char-in-c-closed\/\" aria-label=\"More on [Solved] Pointers and char[] in C [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324,472,712],"class_list":["post-18693","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c","tag-char","tag-pointers"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Pointers and char[] in C [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-pointers-and-char-in-c-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Pointers and char[] in C [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] To know how all these three code blocks works, you got to start reading good C book specially array and pointers concept. Case 1 :- In the below code block int main(void) { char x[] = &quot;gate2011&quot;; char *ptr = x; printf (&quot;%s&quot;, ptr+ptr[3]-ptr[1]); return 0; } It looks like x[0] x[1] x[2] x[3] ... 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Case 1 :- In the below code block int main(void) { char x[] = \"gate2011\"; char *ptr = x; printf (\"%s\", ptr+ptr[3]-ptr[1]); return 0; } It looks like x[0] x[1] x[2] x[3] ... 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