{"id":18598,"date":"2022-11-01T09:32:59","date_gmt":"2022-11-01T04:02:59","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-using-void-methods-in-log-method\/"},"modified":"2022-11-01T09:32:59","modified_gmt":"2022-11-01T04:02:59","slug":"solved-using-void-methods-in-log-method","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-using-void-methods-in-log-method\/","title":{"rendered":"[Solved] using void methods in log method"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-41487128\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"41487128\" data-parentid=\"41486478\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>The <code>void<\/code> keyword is not an object or a variable, all it does is specify that a method does not return anything. So the following line means that the function will return <code>void<\/code> (i.e. nothing):<\/p>\n<pre><code>public void doSomething() {}\n<\/code><\/pre>\n<p>Therefore, using the method <code>Log.i()<\/code> to print <em>nothing<\/em> is not possible. This method expects two <code>String<\/code> objects, which it can print to the logcat. The only reason you can use an <code>int<\/code> is because of the way Java handles <code>String<\/code> concatenation; it automatically converts any primitive type (<code>boolean<\/code>, <code>int<\/code>, <code>float<\/code>, etc.) to a <code>String<\/code> when using the <code>+<\/code> operator.<\/p>\n<hr>\n<p>The reason the <code>Log<\/code> methods expects <em>two<\/em> <code>String<\/code> objects is simply to maintain legibility in logcat. The first parameter is meant to be a <code>TAG<\/code> variable, which is usually the name of the <code>Class<\/code> that is calling the method. This is usually done by creating a static value in each class:<\/p>\n<pre><code>private static final String TAG = MyActivity.class.getSimpleName();\n<\/code><\/pre>\n<p>In this way, you can use the <code>Log<\/code> methods as follows:<\/p>\n<pre><code>Log.i(TAG, \"Log information\u2026\");\n<\/code><\/pre>\n<p>Which will result in a more uniform message written to logcat.<\/p>\n<hr>\n<p>So, with this information, the question remains; what are you trying to output to logcat?<\/p>\n<p>If you just want to output that the method was called, than simply call the <code>Log<\/code> statement before (or after) the method call:<\/p>\n<pre><code>Log.i(TAG, \"doSomething() called\");\ndoSomething();\n<\/code><\/pre>\n<p>Otherwise, if you actually expect your method to <code>return<\/code> a printable result, then you must return something other than <code>void<\/code>. Either a <code>String<\/code>, a primitive type, or an <code>Object<\/code> that can be printed using the <code>toString()<\/code> method.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">8<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved using void methods in log method <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] The void keyword is not an object or a variable, all it does is specify that a method does not return anything. So the following line means that the function will return void (i.e. nothing): public void doSomething() {} Therefore, using the method Log.i() to print nothing is not possible. This method expects two &#8230; <a title=\"[Solved] using void methods in log method\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-using-void-methods-in-log-method\/\" aria-label=\"More on [Solved] using void methods in log method\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[452,2115,3839],"class_list":["post-18598","post","type-post","status-publish","format-standard","hentry","category-solved","tag-android","tag-android-logcat","tag-return-type"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] using void methods in log method - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-using-void-methods-in-log-method\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] using void methods in log method - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] The void keyword is not an object or a variable, all it does is specify that a method does not return anything. So the following line means that the function will return void (i.e. nothing): public void doSomething() {} Therefore, using the method Log.i() to print nothing is not possible. This method expects two ... 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