{"id":18232,"date":"2022-10-30T03:18:06","date_gmt":"2022-10-29T21:48:06","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-dictionary-all-for-one\/"},"modified":"2022-10-30T03:18:06","modified_gmt":"2022-10-29T21:48:06","slug":"solved-dictionary-all-for-one","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-dictionary-all-for-one\/","title":{"rendered":"[Solved] Dictionary all for one"},"content":{"rendered":"

[ad_1]
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First of all, just printing the dictionary itself will print everything on one line:<\/p>\n

>>> dicMyDictionary = {\"michael\":\"jordan\", \"kobe\":\"bryant\", \"lebron\":\"james\"}\n>>> print(dicMyDictionary)\n{'kobe': 'bryant', 'michael': 'jordan', 'lebron': 'james'}\n<\/code><\/pre>\n
If you want to format it in some way:<\/p>\n
>>> print(' '.join(str(key)+\":\"+str(value) for key,value in dicMyDictionary.iteritems()))\nkobe:bryant michael:jordan lebron:james\n<\/code><\/pre>\n
ref: str.join<\/a>, dict.iteritems<\/a><\/p>\n
Or with a for<\/code> loop for more detailed control:<\/p>\n
>>> formatted_str = \"\"\n>>> for key,value in dicMyDictionary.iteritems():\n        formatted_str += \"(key: \" + str(key) + \" value:\" + value + \") \"\n>>> print(formatted_str)\n(key: kobe value:bryant) (key: michael value:jordan) (key: lebron value:james)\n<\/code><\/pre>\n
ref: dict.iteritems<\/a>,Python looping techniques<\/a><\/p>\n<\/p><\/div>\n
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            4<\/span> <\/p><\/div>\n<\/div>\n
[ad_2]<\/p>\n
solved Dictionary all for one <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] First of all, just printing the dictionary itself will print everything on one line: >>> dicMyDictionary = {“michael”:”jordan”, “kobe”:”bryant”, “lebron”:”james”} >>> print(dicMyDictionary) {‘kobe’: ‘bryant’, ‘michael’: ‘jordan’, ‘lebron’: ‘james’} If you want to format it in some way: >>> print(‘ ‘.join(str(key)+”:”+str(value) for key,value in dicMyDictionary.iteritems())) kobe:bryant michael:jordan lebron:james ref: str.join, dict.iteritems Or with a for … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[834,349],"class_list":["post-18232","post","type-post","status-publish","format-standard","hentry","category-solved","tag-dictionary","tag-python"],"yoast_head":"\n[Solved] Dictionary all for one - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-dictionary-all-for-one\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Dictionary all for one - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] First of all, just printing the dictionary itself will print everything on one line: >>> dicMyDictionary = {"michael":"jordan", "kobe":"bryant", "lebron":"james"} >>> print(dicMyDictionary) {'kobe': 'bryant', 'michael': 'jordan', 'lebron': 'james'} If you want to format it in some way: >>> print(' '.join(str(key)+":"+str(value) for key,value in dicMyDictionary.iteritems())) kobe:bryant michael:jordan lebron:james ref: str.join, dict.iteritems Or with a for ... 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