{"id":17602,"date":"2022-10-26T05:26:57","date_gmt":"2022-10-25T23:56:57","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-calculate-and-return-the-difference-between-the-second-largest-number-and-the-second-smallest-number-closed\/"},"modified":"2022-10-26T05:26:57","modified_gmt":"2022-10-25T23:56:57","slug":"solved-calculate-and-return-the-difference-between-the-second-largest-number-and-the-second-smallest-number-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-calculate-and-return-the-difference-between-the-second-largest-number-and-the-second-smallest-number-closed\/","title":{"rendered":"[Solved] calculate and return the difference between the second largest number and the second smallest number [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-55570290\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"55570290\" data-parentid=\"55570042\" data-score=\"0\" data-position-on-page=\"2\" data-highest-scored=\"0\" data-question-has-accepted-highest-score=\"0\" itemprop=\"suggestedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Here is a simple, but not most efficient way. you can achieve that by two step:<\/p>\n<ol>\n<li>convert <code>list<\/code> to <code>set<\/code>, to remove the duplicate number.<\/li>\n<li>use <code>heap<\/code> to find <code>nlargest<\/code> and <code>nsmallest<\/code> in <code>set<\/code><\/li>\n<\/ol>\n<pre><code>def difference(list1):\n    set1 = set(list1)\n    return heapq.nlargest(2, set1)[1] - heapq.nsmallest(2, set1)[1]\n<\/code><\/pre>\n<hr>\n<p>Here is a one pass way, more efficient way, use 4 variables:<\/p>\n<pre><code>def difference(list1):\n    max1, max2, min1, min2 = float('-inf'), float('-inf'), float('inf'), float('inf')\n    for x in list1:\n        if x &gt; max1:\n            max1, max2 = x, max1\n        elif x &gt;= max2 and x != max1:\n            max2 = x\n\n        if x &lt; min1:\n            min1, min2 = x, min1\n        elif x &lt;= min2 and x != min1:\n            min2 = x\n\n    return max2 - min2\n<\/code><\/pre>\n<p>test and output:<\/p>\n<pre><code>print(difference([10, 10, 10, 8, 5, 2, 1, 1, 1]))\n# 6\n<\/code><\/pre>\n<p>Hope that helps you, and comment if you have further questions. : )<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved calculate and return the difference between the second largest number and the second smallest number [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Here is a simple, but not most efficient way. you can achieve that by two step: convert list to set, to remove the duplicate number. use heap to find nlargest and nsmallest in set def difference(list1): set1 = set(list1) return heapq.nlargest(2, set1)[1] &#8211; heapq.nsmallest(2, set1)[1] Here is a one pass way, more efficient way, &#8230; <a title=\"[Solved] calculate and return the difference between the second largest number and the second smallest number [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-calculate-and-return-the-difference-between-the-second-largest-number-and-the-second-smallest-number-closed\/\" aria-label=\"More on [Solved] calculate and return the difference between the second largest number and the second smallest number [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[2555,4355,349,561],"class_list":["post-17602","post","type-post","status-publish","format-standard","hentry","category-solved","tag-nested-lists","tag-numpy-slicing","tag-python","tag-sorting"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] calculate and return the difference between the second largest number and the second smallest number [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-calculate-and-return-the-difference-between-the-second-largest-number-and-the-second-smallest-number-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] calculate and return the difference between the second largest number and the second smallest number [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Here is a simple, but not most efficient way. you can achieve that by two step: convert list to set, to remove the duplicate number. use heap to find nlargest and nsmallest in set def difference(list1): set1 = set(list1) return heapq.nlargest(2, set1)[1] - heapq.nsmallest(2, set1)[1] Here is a one pass way, more efficient way, ... 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