{"id":17455,"date":"2022-10-24T19:28:05","date_gmt":"2022-10-24T13:58:05","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-understanding-function-with-map-lambda-sum-zip-closed\/"},"modified":"2022-10-24T19:28:05","modified_gmt":"2022-10-24T13:58:05","slug":"solved-understanding-function-with-map-lambda-sum-zip-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-understanding-function-with-map-lambda-sum-zip-closed\/","title":{"rendered":"[Solved] Understanding function with map \/ lambda \/ sum \/ zip [closed]"},"content":{"rendered":"

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\n<\/p>\n

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Your function takes 2 iterables and counts the number of times, by index, the number from one iterable is greater than the other. It then does the same operation with lists in the opposite order.<\/p>\n

It’s far easier to show an example:<\/p>\n

def solve(a, b):\n    return map(lambda t: sum([x > y for x, y in zip(*t)]), ((a, b), (b, a)))\n\nL1 = [1, 2, 3, 1]\nL2 = [4, 5, 1, 5]\n\nres = list(solve(L1, L2))  # [1, 3]\n<\/code><\/pre>\n
sum with bool<\/h3>\n
res[0] = 1<\/code> because 1 < 4, 2 < 5, 3 > 1<\/strong>, 1 < 5.<\/p>\n
res[1] = 3<\/code> because 4 > 1<\/strong>, 5 > 2<\/strong>, 1 < 3, 5 > 1<\/strong>.<\/p>\n
Note that sum<\/code> with an iterable of Boolean values consider True<\/code> as 1<\/code> and False<\/code> as 0<\/code>. This is natural because bool<\/code> is implemented as a subclass of int<\/code>. The bold values above are considered True<\/code> and therefore a count of such instances will be the result of a sum<\/code> over those values.<\/p>\n
list comprehension<\/h3>\n
A list comprehension is easier to comprehend:<\/p>\n
res = [sum(i > j for i, j in zip(*L)) for L in ((L1, L2), (L2, L1))]\n<\/code><\/pre>\n
generator expression<\/h3>\n
In fact, since map<\/code> returns a lazy iterator, solve<\/code> more closely resembles a generator expression, which should perform better than the map<\/code> variant:<\/p>\n
res = (sum(i > j for i, j in zip(*L)) for L in ((L1, L2), (L2, L1)))\n<\/code><\/pre>\n
You can then iterate the generator expression:<\/p>\n
for item in res:\n    print(item)\n<\/code><\/pre>\n
Or exhaust the generator via a function such as list<\/code>:<\/p>\n
res_list = list(res)\n<\/code><\/pre>\n<\/p><\/div>\n
<\/div>\n<\/div>\n
            2<\/span> <\/p><\/div>\n<\/div>\n
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solved Understanding function with map \/ lambda \/ sum \/ zip [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Your function takes 2 iterables and counts the number of times, by index, the number from one iterable is greater than the other. It then does the same operation with lists in the opposite order. It’s far easier to show an example: def solve(a, b): return map(lambda t: sum([x > y for x, y … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[350,349,482],"class_list":["post-17455","post","type-post","status-publish","format-standard","hentry","category-solved","tag-iterator","tag-python","tag-python-3-x"],"yoast_head":"\n[Solved] Understanding function with map \/ lambda \/ sum \/ zip [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-understanding-function-with-map-lambda-sum-zip-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Understanding function with map \/ lambda \/ sum \/ zip [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Your function takes 2 iterables and counts the number of times, by index, the number from one iterable is greater than the other. It then does the same operation with lists in the opposite order. It’s far easier to show an example: def solve(a, b): return map(lambda t: sum([x > y for x, y ... 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