{"id":17177,"date":"2022-10-23T09:22:08","date_gmt":"2022-10-23T03:52:08","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-get-value-from-a-table-base-on-preference-closed\/"},"modified":"2022-10-23T09:22:08","modified_gmt":"2022-10-23T03:52:08","slug":"solved-how-to-get-value-from-a-table-base-on-preference-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-get-value-from-a-table-base-on-preference-closed\/","title":{"rendered":"[Solved] How to get value from a table base on &#8220;Preference&#8221; [closed]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-14512057\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"14512057\" data-parentid=\"14511536\" data-score=\"2\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>This might be slightly off as mysql dialect always throws me. Since B falls after A in an alphabetical sort, if you group on the ID and then select the maximum, it will give you all the B rows where they exist, otherwise you will get the A row.<\/p>\n<pre><code>SELECT\n    ID,\n    MAX(alphabet) AS preference\nFROM\n    t1\nGROUP BY\n    ID\n<\/code><\/pre>\n<p>Now, if your data is more complex than what you&#8217;ve indicated, you will need to examine whether the MAX logic still applies.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">3<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved How to get value from a table base on &#8220;Preference&#8221; [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] This might be slightly off as mysql dialect always throws me. Since B falls after A in an alphabetical sort, if you group on the ID and then select the maximum, it will give you all the B rows where they exist, otherwise you will get the A row. SELECT ID, MAX(alphabet) AS preference &#8230; <a title=\"[Solved] How to get value from a table base on &#8220;Preference&#8221; [closed]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-get-value-from-a-table-base-on-preference-closed\/\" aria-label=\"More on [Solved] How to get value from a table base on &#8220;Preference&#8221; [closed]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[639,340],"class_list":["post-17177","post","type-post","status-publish","format-standard","hentry","category-solved","tag-if-statement","tag-mysql"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] How to get value from a table base on &quot;Preference&quot; [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-get-value-from-a-table-base-on-preference-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to get value from a table base on &quot;Preference&quot; [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] This might be slightly off as mysql dialect always throws me. Since B falls after A in an alphabetical sort, if you group on the ID and then select the maximum, it will give you all the B rows where they exist, otherwise you will get the A row. SELECT ID, MAX(alphabet) AS preference ... 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