{"id":16874,"date":"2022-10-22T10:40:10","date_gmt":"2022-10-22T05:10:10","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-math-need-a-number-between-180-and-180\/"},"modified":"2022-10-22T10:40:10","modified_gmt":"2022-10-22T05:10:10","slug":"solved-math-need-a-number-between-180-and-180","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-math-need-a-number-between-180-and-180\/","title":{"rendered":"[Solved] math need a number between -180 and 180"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-30278373\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"30278373\" data-parentid=\"30278099\" data-score=\"0\" data-position-on-page=\"2\" data-highest-scored=\"0\" data-question-has-accepted-highest-score=\"0\" itemprop=\"suggestedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>You could solve it like this:<\/p>\n<pre><code>private static final int MIN = -180;\nprivate static final int MAX = 180;\n\npublic static void main(String[] args) {\n    System.out.println(keepInRange(-150 + 90));\n    System.out.println(keepInRange(0 + 90));\n    System.out.println(keepInRange(150 + 90));\n    System.out.println(keepInRange(-150 - 90));\n}\n\nprivate static int keepInRange(final int value) {\n    if (value &lt; MIN) {\n        \/*\n         * subtract the negative number \"MIN\" from \"value\" and\n         * add the negative result to \"MAX\" (which is like subtracting the absolute value\n         * of \"value\" from \"MAX)\n         *\/\n        return MAX + (value - MIN);\n    }\n    if (value &gt; MAX) {\n        \/*\n         * subtract the number \"MAX\" from \"value\" and to get exceeding number\n         * add it to \"MIN\"\n         *\/\n        return MIN + (value - MAX);\n    }\n    return value;\n}\n<\/code><\/pre>\n<p>The output is:<\/p>\n<blockquote>\n<p>-60<br \/>\n  90<br \/>\n  -120<br \/>\n  120<\/p>\n<\/blockquote>\n<p>According to your explanation, the last to values should be <em>-120<\/em> and <em>120<\/em> and not <em>-60<\/em> and <em>60<\/em> like you said in your example. The exceeding amount should be added to the &#8220;other&#8221; bound, and not from <em>0<\/em>. <code>150 + 90<\/code> is <em>240<\/em>, so it exceeds the MAX bound by 60. This then should be added to the MIN bound. The result is <em>-120<\/em>.<\/p>\n<p>If this is not correct, then please update your question.<\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved math need a number between -180 and 180 <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] You could solve it like this: private static final int MIN = -180; private static final int MAX = 180; public static void main(String[] args) { System.out.println(keepInRange(-150 + 90)); System.out.println(keepInRange(0 + 90)); System.out.println(keepInRange(150 + 90)); System.out.println(keepInRange(-150 &#8211; 90)); } private static int keepInRange(final int value) { if (value &lt; MIN) { \/* * subtract &#8230; <a title=\"[Solved] math need a number between -180 and 180\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-math-need-a-number-between-180-and-180\/\" aria-label=\"More on [Solved] math need a number between -180 and 180\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[323],"class_list":["post-16874","post","type-post","status-publish","format-standard","hentry","category-solved","tag-java"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>[Solved] math need a number between -180 and 180 - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-math-need-a-number-between-180-and-180\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] math need a number between -180 and 180 - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You could solve it like this: private static final int MIN = -180; private static final int MAX = 180; public static void main(String[] args) { System.out.println(keepInRange(-150 + 90)); System.out.println(keepInRange(0 + 90)); System.out.println(keepInRange(150 + 90)); System.out.println(keepInRange(-150 - 90)); } private static int keepInRange(final int value) { if (value &lt; MIN) { \/* * subtract ... 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