{"id":16780,"date":"2022-10-22T03:55:32","date_gmt":"2022-10-21T22:25:32","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-is-there-an-efficient-method-to-check-for-8-successive-elements-that-are-not-na-i-e-is-nafalse-in-each-column-of-a-large-dataset\/"},"modified":"2022-10-22T03:55:32","modified_gmt":"2022-10-21T22:25:32","slug":"solved-is-there-an-efficient-method-to-check-for-8-successive-elements-that-are-not-na-i-e-is-nafalse-in-each-column-of-a-large-dataset","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-is-there-an-efficient-method-to-check-for-8-successive-elements-that-are-not-na-i-e-is-nafalse-in-each-column-of-a-large-dataset\/","title":{"rendered":"[Solved] Is there an efficient method to check for 8 successive elements that are not NA (i.e. is.na()==FALSE) in each column of a large dataset?"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-59921254\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"59921254\" data-parentid=\"59917833\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>The following code does what the question asks for.<br \/>\nThe function that does all the work is <code>append_one<\/code>. It<\/p>\n<ol>\n<li>Creates a vector <code>Y<\/code> repeating the prefix <code>length(x)<\/code> times.<\/li>\n<li>Gets the runs of vector <code>y<\/code>.<\/li>\n<li>Cleans the runs&#8217; values to the empty string <code>\"\"<\/code> if the runs&#8217; lengths are less than <code>N<\/code>.<\/li>\n<li>Reverses the run-length encoding.<\/li>\n<li>Pastes this vector of prefixes with the input vector <code>x<\/code>.<\/li>\n<\/ol>\n<p>Then function <code>append_all<\/code> calls this function on every column of the input data frame.<\/p>\n<pre><code>append_one &lt;- function(x, N, pref = \"D\"){\n  y &lt;- rep(pref, length(x))\n  is.na(y) &lt;- is.na(x)\n  r &lt;- rle(y)\n  r$values[r$lengths &lt; N] &lt;- \"\"\n  y &lt;- inverse.rle(r)\n  paste0(y, x)\n}\n\nappend_all &lt;- function(X, n, pref = \"D\"){\n  Y &lt;- X\n  Y [] &lt;- lapply(Y, append_one, N = n, pref = pref)\n  Y\n}\n\nN1 &lt;- 3\nappend_all(df1, N1)\n<\/code><\/pre>\n<p><strong>Data.<\/strong>  <\/p>\n<p>Original data set, posted in the question.<\/p>\n<pre><code>df &lt;- data.frame(c(1,NA,1,1,1),\n                  c(2,2,NA,NA,NA),\n                  c(3,3,3,3,NA),\n                  c(4,4,4,4,4),\n                  c(5,NA,5,NA,5))\n<\/code><\/pre>\n<p>New data set and corresponding output, posted in a comment.<\/p>\n<pre><code>df1 &lt;- data.frame(c(1.0,NA,1.1,1.2,1.3),\n                  c(2.0,2.1,NA,NA,NA),\n                  c(3.0,3.1,3.2,3.3,NA),\n                  c(4.0,4.1,4.2,4.3,4.4),\n                  c(5.0,NA,5.1,NA,5.2))\n\ndf2 &lt;- data.frame(c(1.0,NA,'D1.1','D1.2','D1.3'),\n                  c(2.0,2.1,NA,NA,NA),\n                  c('D3.0','D3.1','D3.2','D3.3',NA),\n                  c('D4.0','D4.1','D4.2','D4.3','D4.4'),\n                  c(5.0,NA,5.1,NA,5.2))\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">4<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Is there an efficient method to check for 8 successive elements that are not NA (i.e. is.na()==FALSE) in each column of a large dataset? <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] The following code does what the question asks for. The function that does all the work is append_one. It Creates a vector Y repeating the prefix length(x) times. Gets the runs of vector y. Cleans the runs&#8217; values to the empty string &#8220;&#8221; if the runs&#8217; lengths are less than N. Reverses the run-length &#8230; <a title=\"[Solved] Is there an efficient method to check for 8 successive elements that are not NA (i.e. is.na()==FALSE) in each column of a large dataset?\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-is-there-an-efficient-method-to-check-for-8-successive-elements-that-are-not-na-i-e-is-nafalse-in-each-column-of-a-large-dataset\/\" aria-label=\"More on [Solved] Is there an efficient method to check for 8 successive elements that are not NA (i.e. is.na()==FALSE) in each column of a large dataset?\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[321],"class_list":["post-16780","post","type-post","status-publish","format-standard","hentry","category-solved","tag-r"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Is there an efficient method to check for 8 successive elements that are not NA (i.e. is.na()==FALSE) in each column of a large dataset? - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-is-there-an-efficient-method-to-check-for-8-successive-elements-that-are-not-na-i-e-is-nafalse-in-each-column-of-a-large-dataset\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Is there an efficient method to check for 8 successive elements that are not NA (i.e. is.na()==FALSE) in each column of a large dataset? - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] The following code does what the question asks for. 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