{"id":16698,"date":"2022-10-21T22:33:06","date_gmt":"2022-10-21T17:03:06","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-list-in-list-changes-but-var-in-list-not-duplicate\/"},"modified":"2022-10-21T22:33:06","modified_gmt":"2022-10-21T17:03:06","slug":"solved-list-in-list-changes-but-var-in-list-not-duplicate","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-list-in-list-changes-but-var-in-list-not-duplicate\/","title":{"rendered":"[Solved] List in list changes but var in list not? [duplicate]"},"content":{"rendered":"

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The problem you’re experiencing is due to a misunderstanding of lists, list-references, and possibly the concept of mutability.<\/p>\n

In your case, you are binding the name user_data<\/code> to a list object. In other words, user_data<\/code> acts as a list-reference to the actual list object in memory.<\/p>\n

When you say user_list.append(user_data)<\/code>, all you’re doing is appending a list-reference to user_list<\/code>. It doesn’t make a deep copy, or anything like that.
\nSo, if you have two username-password-pairs, then you’ll have two list-references, both pointing to the same underlying list in memory. Any change you make to the list object through any of its references will be reflected in all other references, since they’re all just “pointing” to the same place.<\/p>\n

>>> empty_list = []\n>>> lists = [empty_list, empty_list]\n>>> lists[0]\n[]\n>>> lists[1]\n[]\n>>> lists[0].append(1)\n>>> lists[0]\n[1]\n>>> lists[1]\n[1]\n>>> \n<\/code><\/pre>\n<\/p><\/div>\n
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            <\/span> <\/p><\/div>\n<\/div>\n
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solved List in list changes but var in list not? [duplicate] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] The problem you’re experiencing is due to a misunderstanding of lists, list-references, and possibly the concept of mutability. In your case, you are binding the name user_data to a list object. In other words, user_data acts as a list-reference to the actual list object in memory. When you say user_list.append(user_data), all you’re doing is … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[540,349,366],"class_list":["post-16698","post","type-post","status-publish","format-standard","hentry","category-solved","tag-list","tag-python","tag-variables"],"yoast_head":"\n[Solved] List in list changes but var in list not? [duplicate] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-list-in-list-changes-but-var-in-list-not-duplicate\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] List in list changes but var in list not? [duplicate] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] The problem you’re experiencing is due to a misunderstanding of lists, list-references, and possibly the concept of mutability. In your case, you are binding the name user_data to a list object. In other words, user_data acts as a list-reference to the actual list object in memory. When you say user_list.append(user_data), all you’re doing is ... 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