{"id":16399,"date":"2022-10-15T20:02:39","date_gmt":"2022-10-15T14:32:39","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-positive-negative-and-zero-assembly\/"},"modified":"2022-10-15T20:02:39","modified_gmt":"2022-10-15T14:32:39","slug":"solved-positive-negative-and-zero-assembly","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-positive-negative-and-zero-assembly\/","title":{"rendered":"[Solved] Positive, negative and zero (assembly)"},"content":{"rendered":"

[ad_1]
\n<\/p>\n

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What’s wrong with my code?<\/p>\n<\/blockquote>\n

I only had a quick look at your program, so my answer may be wrong:<\/p>\n

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LDD 0,Y\n<\/code><\/pre>\n<\/blockquote>\n
Obviously you are operating with 16 bit numbers. Otherwise you would use LDA<\/code> or LDB<\/code> instead of LDD<\/code>.<\/p>\n
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CPY #(ARRAY+QUANTITY-1)\n<\/code><\/pre>\n<\/blockquote>\n
This would be correct if QUANTITY<\/code> is the size of the array in bytes (e.g. 30 in the case of int A[15]<\/code>).<\/p>\n
If QUANTITY<\/code> is the number of elements and you are operating with 16-bit numbers, you have to multiply with two:<\/p>\n
CPY #(ARRAY+2*QUANTITY-1)\n<\/code><\/pre>\n
\n
INY\n<\/code><\/pre>\n<\/blockquote>\n
Once again this would work for 8-bit elements. For 16-bit elements you have to add two to each element or to increment Y<\/code> twice:<\/p>\n
INY\nINY\n<\/code><\/pre>\n
\n
INY\nBLT NEGATIVE_NUMBER\n<\/code><\/pre>\n<\/blockquote>\n
The INY<\/code> instruction will modify the zero flag and therefore influence the BLT<\/code>, BGE<\/code> and BEQ<\/code> instructions. You cannot use INY<\/code> between LDD<\/code> and the branch instructions.<\/p>\n
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BLT ...\nBEQ ...\nBGE ...\n<\/code><\/pre>\n<\/blockquote>\n
Not really an error, but the BGE<\/code> instruction will always branch. You may place the POSITIVE_NUMBER<\/code> number code after the BEQ<\/code> instruction and remove the BGE<\/code> instruction.<\/p>\n
EDIT<\/strong><\/p>\n
\n
I’m not understanding this part: INY<\/code> followed by Bxx<\/code><\/p>\n<\/blockquote>\n
I was thinking about three different ways to do this. The simplest one seems to be:<\/p>\n
    LDY #(ARRAY-2)  ; Because we'll do INY twice right now\nLOOP\n    INY\n    INY\n    CPY #(ARRAY+2*QUANTITY-1)\n    BHI END\n    LDD 0,Y\n    BLT NEGATIVE_NUMBER\n    ...\n<\/code><\/pre>\n<\/p><\/div>\n
<\/div>\n<\/div>\n
            9<\/span> <\/p><\/div>\n<\/div>\n
[ad_2]<\/p>\n
solved Positive, negative and zero (assembly) <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] What’s wrong with my code? I only had a quick look at your program, so my answer may be wrong: LDD 0,Y Obviously you are operating with 16 bit numbers. Otherwise you would use LDA or LDB instead of LDD. CPY #(ARRAY+QUANTITY-1) This would be correct if QUANTITY is the size of the array … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[4166,465],"class_list":["post-16399","post","type-post","status-publish","format-standard","hentry","category-solved","tag-68hc11","tag-assembly"],"yoast_head":"\n[Solved] Positive, negative and zero (assembly) - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-positive-negative-and-zero-assembly\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Positive, negative and zero (assembly) - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] What’s wrong with my code? I only had a quick look at your program, so my answer may be wrong: LDD 0,Y Obviously you are operating with 16 bit numbers. Otherwise you would use LDA or LDB instead of LDD. CPY #(ARRAY+QUANTITY-1) This would be correct if QUANTITY is the size of the array ... 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I only had a quick look at your program, so my answer may be wrong: LDD 0,Y Obviously you are operating with 16 bit numbers. Otherwise you would use LDA or LDB instead of LDD. CPY #(ARRAY+QUANTITY-1) This would be correct if QUANTITY is the size of the array ... 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