{"id":15538,"date":"2022-10-12T01:22:43","date_gmt":"2022-10-11T19:52:43","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-change-position-of-an-element-in-an-array\/"},"modified":"2022-10-12T01:22:43","modified_gmt":"2022-10-11T19:52:43","slug":"solved-how-to-change-position-of-an-element-in-an-array","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-change-position-of-an-element-in-an-array\/","title":{"rendered":"[Solved] How to change position of an element in an array?"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-42459522\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"42459522\" data-parentid=\"42458612\" data-score=\"0\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>If you can do an increment of one, just repeat that the required number of times.<\/p>\n<p>A better way would be: (let&#8217;s call the increment <em>n<\/em>); store the end <em>n<\/em> elements in another array; move the elements before that towards the end of the array; copy back the elements from the other array to the start. Like this:<\/p>\n<pre><code>Module Module1\n\n    Sub Main()\n        Dim players() As String = {\"Adam\", \"Becky\", \"Clive\", \"Debby\", \"Edward\", \"Fiona\"}\n        Dim rotateBy = 2\n\n        ' make sure shiftBy is in a usable range\n        rotateBy = rotateBy Mod players.Length\n        ' if shiftBy is negative, make it positive such that a left-rotate is performed\n        If rotateBy &lt; 0 Then\n            rotateBy = rotateBy + players.Length\n        End If\n\n        ' store the elements which will be moved to the other end of the array\n        Dim tmp(rotateBy - 1) As String\n        Dim startIndex = players.Length - rotateBy\n        For i = startIndex To players.Length - 1\n            tmp(i - startIndex) = players(i)\n        Next\n\n        ' move the elements\n        For i = players.Length - 1 - rotateBy To 0 Step -1\n            players(i + rotateBy) = players(i)\n        Next\n\n        'fill in the other elements\n        For i = 0 To rotateBy - 1\n            players(i) = tmp(i)\n        Next\n\n        ' show the result\n        Console.WriteLine(String.Join(\", \", players))\n\n        Console.ReadLine()\n\n    End Sub\n\nEnd Module\n<\/code><\/pre>\n<p>Note that the copying of elements within the <code>players<\/code> array is done backwards so that an overlapping range does not splat over values which have yet to be moved.<\/p>\n<p>To shift the elements backwards, use a negative value for <code>rotateBy<\/code>.<\/p>\n<p>If you are using a language with a function which gives array copying functions, this method is easy to adapt to use that functionality. For anyone wondering about that in the future:<\/p>\n<pre><code>Module Module1\n\n    Sub Main()\n        Dim players() As String = {\"Adam\", \"Becky\", \"Clive\", \"Debby\", \"Edward\", \"Fiona\"}\n        Dim rotateBy = 4\n\n        ' make sure shiftBy is in a usable range\n        rotateBy = rotateBy Mod players.Length\n        ' if shiftBy is negative, make it positive such that a left-rotate is performed\n        If rotateBy &lt; 0 Then\n            rotateBy = rotateBy + players.Length\n        End If\n\n        ' store the elements which will be moved to the other end of the array\n        Dim tmp(rotateBy - 1) As String\n        Dim startIndex = players.Length - rotateBy\n\n        Array.Copy(players, startIndex, tmp, 0, rotateBy)\n        Array.Copy(players, 0, players, rotateBy, startIndex)\n        Array.Copy(tmp, players, tmp.Length)\n\n        ' show the result\n        Console.WriteLine(String.Join(\", \", players))\n\n        Console.ReadLine()\n\n    End Sub\n\nEnd Module\n<\/code><\/pre>\n<hr>\n<p>As you mentioned <em>any<\/em> programming language, this is what it could be in C# as a function but without using any framework methods such as <code>Array.Copy<\/code>:<\/p>\n<pre><code>public static void RotateUsingLoops&lt;T&gt;(T[] elements, int rotateBy)\n{\n    rotateBy = rotateBy % elements.Length;\n    if (rotateBy &lt; 0)\n    {\n        rotateBy += elements.Length;\n    }\n    T[] tmp = new T[rotateBy];\n    int startIndex = elements.Length - rotateBy;\n\n    \/\/ store the elements which will be moved to the other end of the array\n    for (int i = startIndex; i &lt; elements.Length; i++)\n    {\n        tmp[i - startIndex] = elements[i];\n    }\n\n    \/\/ move the elements\n    for (int i = elements.Length - 1 - rotateBy; i &gt;= 0; i--)\n    {\n        elements[i + rotateBy] = elements[i];\n    }\n\n    \/\/ fill in the other elements\n    for (int i = 0; i &lt; rotateBy; i++)\n    {\n        elements[i] = tmp[i];\n    }\n}\n<\/code><\/pre>\n<p>Whereby you could use<\/p>\n<pre><code>static void Main(string[] args)\n{\n    var a = new string[] { \"A\", \"B\", \"C\", \"D\" };\n    RotateUsingLoops(a, 2);\n    Console.WriteLine(string.Join(\", \", a));\n\n    Console.ReadLine();\n\n}\n<\/code><\/pre>\n<p>to get an output of:<\/p>\n<blockquote>\n<p>C, D, A, B<\/p>\n<\/blockquote><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">0<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved How to change position of an element in an array? <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] If you can do an increment of one, just repeat that the required number of times. A better way would be: (let&#8217;s call the increment n); store the end n elements in another array; move the elements before that towards the end of the array; copy back the elements from the other array to &#8230; <a title=\"[Solved] How to change position of an element in an array?\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-change-position-of-an-element-in-an-array\/\" aria-label=\"More on [Solved] How to change position of an element in an array?\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[361,353],"class_list":["post-15538","post","type-post","status-publish","format-standard","hentry","category-solved","tag-arrays","tag-vb-net"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] How to change position of an element in an array? - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-change-position-of-an-element-in-an-array\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to change position of an element in an array? - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] If you can do an increment of one, just repeat that the required number of times. 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