{"id":14448,"date":"2022-10-07T21:26:32","date_gmt":"2022-10-07T15:56:32","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-my-question-is-about-the-prime-number-code-that-it-display-multiple-of-three\/"},"modified":"2022-10-07T21:26:32","modified_gmt":"2022-10-07T15:56:32","slug":"solved-my-question-is-about-the-prime-number-code-that-it-display-multiple-of-three","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-my-question-is-about-the-prime-number-code-that-it-display-multiple-of-three\/","title":{"rendered":"[Solved] My Question is about the prime number code that it display multiple of three"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-57867757\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"57867757\" data-parentid=\"57867623\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Try this inside the loop with j as counter variable. This ensures that all the numbers from 2 to j-1 are not factors of j. Also check on other methods of prime number generation like <b>Sieve of Eratosthenes<\/b>, or reducing the complexity of this code by running loop till <code>sqrt(j)<\/code> <\/p>\n<pre><code>counter=0;\nfor(i=2;i&lt;j;i++){\n    if(j%i==0){\n        counter=1;\n        break;\n    }\n}\nif(counter==0){\n    System.out.println(j);\n}\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved My Question is about the prime number code that it display multiple of three <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Try this inside the loop with j as counter variable. This ensures that all the numbers from 2 to j-1 are not factors of j. Also check on other methods of prime number generation like Sieve of Eratosthenes, or reducing the complexity of this code by running loop till sqrt(j) counter=0; for(i=2;i&lt;j;i++){ if(j%i==0){ counter=1; &#8230; <a title=\"[Solved] My Question is about the prime number code that it display multiple of three\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-my-question-is-about-the-prime-number-code-that-it-display-multiple-of-three\/\" aria-label=\"More on [Solved] My Question is about the prime number code that it display multiple of three\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[323],"class_list":["post-14448","post","type-post","status-publish","format-standard","hentry","category-solved","tag-java"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] My Question is about the prime number code that it display multiple of three - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-my-question-is-about-the-prime-number-code-that-it-display-multiple-of-three\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] My Question is about the prime number code that it display multiple of three - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Try this inside the loop with j as counter variable. This ensures that all the numbers from 2 to j-1 are not factors of j. Also check on other methods of prime number generation like Sieve of Eratosthenes, or reducing the complexity of this code by running loop till sqrt(j) counter=0; for(i=2;i&lt;j;i++){ if(j%i==0){ counter=1; ... 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This ensures that all the numbers from 2 to j-1 are not factors of j. Also check on other methods of prime number generation like Sieve of Eratosthenes, or reducing the complexity of this code by running loop till sqrt(j) counter=0; for(i=2;i&lt;j;i++){ if(j%i==0){ counter=1; ... 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