{"id":14204,"date":"2022-10-06T21:40:06","date_gmt":"2022-10-06T16:10:06","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-get-the-total-sum-of-currency-from-a-nsmutablearray-duplicate\/"},"modified":"2022-10-06T21:40:06","modified_gmt":"2022-10-06T16:10:06","slug":"solved-how-get-the-total-sum-of-currency-from-a-nsmutablearray-duplicate","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-get-the-total-sum-of-currency-from-a-nsmutablearray-duplicate\/","title":{"rendered":"[Solved] How get the total sum of currency from a NSMutableArray [duplicate]"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-23325789\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"23325789\" data-parentid=\"23325660\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>If the values are stored as <code>NSNumber<\/code> objects, you can use the collection operators. For example:<\/p>\n<pre><code>NSArray *array = @[@1234.56, @2345.67];\nNSNumber *sum = [array valueForKeyPath:@\"@sum.self\"];\n<\/code><\/pre>\n<p>If you want to format that <code>sum<\/code> nicely using <code>NSNumberFormatter<\/code>:<\/p>\n<pre><code>NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];\nformatter.numberStyle = NSNumberFormatterDecimalStyle;\nNSString *result = [formatter stringFromNumber:sum];\n\nNSLog(@\"result = %@\", result);\n<\/code><\/pre>\n<hr>\n<p>If your values are really represented by strings, <code>@\"1,234.56\"<\/code>, <code>@\"2,345.67\"<\/code>, etc., then you might want to manually iterate through the array, converting them to numeric values using the <code>NSNumberFormatter<\/code>, adding them up as you go along:<\/p>\n<pre><code>NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];\nformatter.numberStyle = NSNumberFormatterDecimalStyle;\n\nNSArray *array = @[@\"1,234.56\", @\"2,345.67\"];\n\ndouble sum = 0.0;\n\nfor (NSString *string in array) {\n    sum += [[formatter numberFromString:string] doubleValue];\n}\n\nNSString *result = [formatter stringFromNumber:@(sum)];\n\nNSLog(@\"result = %@\", result);\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">2<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved How get the total sum of currency from a NSMutableArray [duplicate] <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] If the values are stored as NSNumber objects, you can use the collection operators. For example: NSArray *array = @[@1234.56, @2345.67]; NSNumber *sum = [array valueForKeyPath:@&#8221;@sum.self&#8221;]; If you want to format that sum nicely using NSNumberFormatter: NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; formatter.numberStyle = NSNumberFormatterDecimalStyle; NSString *result = [formatter stringFromNumber:sum]; NSLog(@&#8221;result = %@&#8221;, result); &#8230; <a title=\"[Solved] How get the total sum of currency from a NSMutableArray [duplicate]\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-get-the-total-sum-of-currency-from-a-nsmutablearray-duplicate\/\" aria-label=\"More on [Solved] How get the total sum of currency from a NSMutableArray [duplicate]\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[471,1122,1097],"class_list":["post-14204","post","type-post","status-publish","format-standard","hentry","category-solved","tag-ios","tag-nsarray","tag-sum"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] How get the total sum of currency from a NSMutableArray [duplicate] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-get-the-total-sum-of-currency-from-a-nsmutablearray-duplicate\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How get the total sum of currency from a NSMutableArray [duplicate] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] If the values are stored as NSNumber objects, you can use the collection operators. For example: NSArray *array = @[@1234.56, @2345.67]; NSNumber *sum = [array valueForKeyPath:@&quot;@sum.self&quot;]; If you want to format that sum nicely using NSNumberFormatter: NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; formatter.numberStyle = NSNumberFormatterDecimalStyle; NSString *result = [formatter stringFromNumber:sum]; NSLog(@&quot;result = %@&quot;, result); ... 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For example: NSArray *array = @[@1234.56, @2345.67]; NSNumber *sum = [array valueForKeyPath:@\"@sum.self\"]; If you want to format that sum nicely using NSNumberFormatter: NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; formatter.numberStyle = NSNumberFormatterDecimalStyle; NSString *result = [formatter stringFromNumber:sum]; NSLog(@\"result = %@\", result); ... 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