{"id":13970,"date":"2022-10-06T02:29:06","date_gmt":"2022-10-05T20:59:06","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-is-there-any-way-i-can-generate-the-following-series-closed\/"},"modified":"2022-10-06T02:29:06","modified_gmt":"2022-10-05T20:59:06","slug":"solved-is-there-any-way-i-can-generate-the-following-series-closed","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-is-there-any-way-i-can-generate-the-following-series-closed\/","title":{"rendered":"[Solved] Is there any way I can generate the following series? [closed]"},"content":{"rendered":"

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Here is one possible solution for your sequence generator.<\/p>\n

#include <iostream>\n#include <string>\n\n\/\/ generate inverted term s -> !s\nstd::string invert(const std::string& s) {\n    const char a=\"1\";\n    const char b = '2';\n    std::string out;\n    for (int i = 0; i < s.size(); i++) {\n        \/\/ here one can check for invalid input as well, eg 0\n        out += s[i] == a ? b : a;\n    }\n    return out;\n}\n\n\/\/ sk = s(k - 1)(!s(k - 1))(!s(k - 1))s(k - 1)\nstd::string nextSeq(const std::string& s) {\n    std::string s_inv = invert(s);\n    return s + s_inv + s_inv + s;\n}\n\n\/\/ generate nth term of the sequence.\nstd::string nthSeq(const std::string& s, const int n) {\n    std::string out = s;\n    for (int i = 1; i < n; i++) {\n        out = nextSeq(out);\n    }\n    return out;\n}\n\nint main() {\n    std::string s1 = \"1221\";\n    \/\/ this will 2nd term 1221211221121221\n    std::cout << nthSeq(s1, 2) << std::endl;\n    return 0;\n}\n<\/code><\/pre>\n<\/p><\/div>\n
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solved Is there any way I can generate the following series? [closed] <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Here is one possible solution for your sequence generator. #include <iostream> #include <string> \/\/ generate inverted term s -> !s std::string invert(const std::string& s) { const char a=”1″; const char b = ‘2’; std::string out; for (int i = 0; i < s.size(); i++) { \/\/ here one can check for invalid input as … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324],"class_list":["post-13970","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c"],"yoast_head":"\n[Solved] Is there any way I can generate the following series? [closed] - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-is-there-any-way-i-can-generate-the-following-series-closed\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Is there any way I can generate the following series? [closed] - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Here is one possible solution for your sequence generator. #include <iostream> #include <string> \/\/ generate inverted term s -> !s std::string invert(const std::string& s) { const char a="1"; const char b = '2'; std::string out; for (int i = 0; i < s.size(); i++) { \/\/ here one can check for invalid input as ... 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