{"id":13273,"date":"2022-10-03T14:42:01","date_gmt":"2022-10-03T09:12:01","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-frequency-count-of-a-column-based-on-two-other-columns\/"},"modified":"2022-10-03T14:42:01","modified_gmt":"2022-10-03T09:12:01","slug":"solved-frequency-count-of-a-column-based-on-two-other-columns","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-frequency-count-of-a-column-based-on-two-other-columns\/","title":{"rendered":"[Solved] frequency count of a column based on two other columns"},"content":{"rendered":"

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You are actually close to the solution. I also want to stress to first check out how to make a good reproducible example (at least for your next question) –>
\nHow to make a great R reproducible example?<\/p>\n

Here comes an example how it might look for your data: <\/p>\n

        # Make up some demo data\n\n    Ticker <- sample(c(\"A\",\"B\",\"C\",\"D\"), size = 100, replace = TRUE)\n    Year <- sample(c(2008,2009,2010), 100, TRUE)\n    Value <- sample(c(0.22, NA), 100, TRUE)\n\n    data <- data.frame(Ticker,Year,Value)\n\n    # open dplyr library\n    library(dplyr)\n\n    #Group data by Ticker and year and count Values that are not NA \n    data %>% group_by(Ticker, Year) %>% summarise(count = length(Value[!is.na(Value)]))\n\n   Ticker  Year count\n   <fctr> <dbl> <int>\n1       A  2008     9\n2       A  2009    11\n3       A  2010     7\n4       B  2008    11\n5       B  2009     2\n6       B  2010     6\n7       C  2008     7\n8       C  2009    10\n9       C  2010     9\n10      D  2008     5\n11      D  2009    12\n12      D  2010    11\n<\/code><\/pre>\n<\/p><\/div>\n
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solved frequency count of a column based on two other columns <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] You are actually close to the solution. I also want to stress to first check out how to make a good reproducible example (at least for your next question) –> How to make a great R reproducible example? Here comes an example how it might look for your data: # Make up some demo … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[461],"class_list":["post-13273","post","type-post","status-publish","format-standard","hentry","category-solved","tag-dataframe"],"yoast_head":"\n[Solved] frequency count of a column based on two other columns - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-frequency-count-of-a-column-based-on-two-other-columns\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] frequency count of a column based on two other columns - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You are actually close to the solution. 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