{"id":13123,"date":"2022-10-03T02:00:54","date_gmt":"2022-10-02T20:30:54","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-what-would-be-the-output-of-a-a-a-with-a-1\/"},"modified":"2022-10-03T02:00:54","modified_gmt":"2022-10-02T20:30:54","slug":"solved-what-would-be-the-output-of-a-a-a-with-a-1","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-what-would-be-the-output-of-a-a-a-with-a-1\/","title":{"rendered":"[Solved] What would be the output of $a + $a++ + $a++ with $a = 1"},"content":{"rendered":"

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This might be better explained with a shorter example:<\/p>\n

$a = 1;\necho $a + $a++;\n<\/code><\/pre>\n
This might look like it should equal 2. The post-increment operator ($a++<\/code>) returns the “before” value of the variable, so it should return 1. And 1+1 equals 2.<\/p>\n
However, what’s actually happening is that $a++<\/code> is getting evaluated first. So the post-increment operator runs, and returns 1, but by the time the rest of the evaluation happens, $a<\/code> has been incremented to 2. So this ends up evaluating 2 + 1<\/code>;<\/p>\n
Your example comes down to:<\/p>\n