{"id":12936,"date":"2022-10-02T11:55:05","date_gmt":"2022-10-02T06:25:05","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-does-malloc-create-a-new-instance-of-the-class-or-not-duplicate\/"},"modified":"2022-10-02T11:55:05","modified_gmt":"2022-10-02T06:25:05","slug":"solved-does-malloc-create-a-new-instance-of-the-class-or-not-duplicate","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-does-malloc-create-a-new-instance-of-the-class-or-not-duplicate\/","title":{"rendered":"[Solved] Does malloc create a new instance of the class or not? [duplicate]"},"content":{"rendered":"

[ad_1]
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The compiler will translate a call to a member function into a call to a static function, with an implied this<\/code> parameter pointing to the object. That means the contents of the object, valid or invalid, are not relevant to the whether the call is made.<\/p>\n

This changes if the method is virtual, since the vtable pointer must be valid. The constructor will initialize the vtable pointer. malloc<\/code> does not<\/em> call the constructor, it doesn’t even know what a constructor is – it’s leftover baggage from C.<\/p>\n

Note that this is not<\/em> specified by the standard, but is how things are typically implemented.<\/p>\n<\/p><\/div>\n

<\/div>\n<\/div>\n

8<\/span> <\/p><\/div>\n<\/div>\n

[ad_2]<\/p>\n

solved Does malloc create a new instance of the class or not? [duplicate] <\/p>\n","protected":false},"excerpt":{"rendered":"

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