{"id":12503,"date":"2022-09-30T23:21:12","date_gmt":"2022-09-30T17:51:12","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-multiple-aggregation-in-r-with-4-parameters\/"},"modified":"2022-09-30T23:21:12","modified_gmt":"2022-09-30T17:51:12","slug":"solved-multiple-aggregation-in-r-with-4-parameters","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-multiple-aggregation-in-r-with-4-parameters\/","title":{"rendered":"[Solved] Multiple aggregation in R with 4 parameters"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-24226262\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"24226262\" data-parentid=\"24226243\" data-score=\"1\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>You could try something like this in <code>data.table<\/code><\/p>\n<pre><code>data &lt;- data.table(yourdataframe)\n\nbar &lt;- data[,.N,by=y]\nfoo &lt;- data[x==1 &amp; z==1,list(mean.t=mean(t,na.rm=T),median.t=median(t,na.rm=T)),by=y]\nmerge(bar[,list(y)],foo,by=\"y\",all.x=T)\n\n   y mean.t median.t\n1: 1   12.5     12.5\n2: 2     NA       NA\n3: 3     NA       NA\n4: 4     NA       NA\n<\/code><\/pre>\n<p>You probably could do the same in  <code>aggregate<\/code>, but I am not sure you can do it in one easy step.  <\/p>\n<p>An answer to to an additional request in the comments&#8230;<\/p>\n<pre><code>bar &lt;- data.table(expand.grid(y=unique(data$y),z=unique(data[z %in% c(1,2,3,4),z])))\nfoo &lt;- data[x==1 &amp; z %in% c(1,2,3,4),list(\n  mean.t=mean(t,na.rm=T),\n  median.t=median(t,na.rm=T),\n  Q25.t=quantile(t,0.25,na.rm=T),\n  Q75.t=quantile(t,0.75,na.rm=T)\n  ),by=list(y,z)]\nmerge(bar[,list(y,z)],foo,by=c(\"y\",\"z\"),all.x=T)\n\n    y z mean.t median.t Q25.t Q75.t\n 1: 1 1   12.5     12.5 11.25 13.75\n 2: 1 2     NA       NA    NA    NA\n 3: 1 3     NA       NA    NA    NA\n 4: 1 4     NA       NA    NA    NA\n 5: 2 1     NA       NA    NA    NA\n 6: 2 2     NA       NA    NA    NA\n 7: 2 3     NA       NA    NA    NA\n 8: 2 4     NA       NA    NA    NA\n 9: 3 1     NA       NA    NA    NA\n10: 3 2     NA       NA    NA    NA\n11: 3 3     NA       NA    NA    NA\n12: 3 4     NA       NA    NA    NA\n13: 4 1     NA       NA    NA    NA\n14: 4 2   18.0     18.0 18.00 18.00\n15: 4 3   45.0     45.0 45.00 45.00\n16: 4 4     NA       NA    NA    NA\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">11<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Multiple aggregation in R with 4 parameters <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] You could try something like this in data.table data &lt;- data.table(yourdataframe) bar &lt;- data[,.N,by=y] foo &lt;- data[x==1 &amp; z==1,list(mean.t=mean(t,na.rm=T),median.t=median(t,na.rm=T)),by=y] merge(bar[,list(y)],foo,by=&#8221;y&#8221;,all.x=T) y mean.t median.t 1: 1 12.5 12.5 2: 2 NA NA 3: 3 NA NA 4: 4 NA NA You probably could do the same in aggregate, but I am not sure you can &#8230; <a title=\"[Solved] Multiple aggregation in R with 4 parameters\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-multiple-aggregation-in-r-with-4-parameters\/\" aria-label=\"More on [Solved] Multiple aggregation in R with 4 parameters\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[3068,321],"class_list":["post-12503","post","type-post","status-publish","format-standard","hentry","category-solved","tag-aggregate","tag-r"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Multiple aggregation in R with 4 parameters - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-multiple-aggregation-in-r-with-4-parameters\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Multiple aggregation in R with 4 parameters - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You could try something like this in data.table data &lt;- data.table(yourdataframe) bar &lt;- data[,.N,by=y] foo &lt;- data[x==1 &amp; z==1,list(mean.t=mean(t,na.rm=T),median.t=median(t,na.rm=T)),by=y] merge(bar[,list(y)],foo,by=&quot;y&quot;,all.x=T) y mean.t median.t 1: 1 12.5 12.5 2: 2 NA NA 3: 3 NA NA 4: 4 NA NA You probably could do the same in aggregate, but I am not sure you can ... 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JassWeb","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/jassweb.com\/solved\/solved-multiple-aggregation-in-r-with-4-parameters\/","og_locale":"en_US","og_type":"article","og_title":"[Solved] Multiple aggregation in R with 4 parameters - JassWeb","og_description":"[ad_1] You could try something like this in data.table data &lt;- data.table(yourdataframe) bar &lt;- data[,.N,by=y] foo &lt;- data[x==1 &amp; z==1,list(mean.t=mean(t,na.rm=T),median.t=median(t,na.rm=T)),by=y] merge(bar[,list(y)],foo,by=\"y\",all.x=T) y mean.t median.t 1: 1 12.5 12.5 2: 2 NA NA 3: 3 NA NA 4: 4 NA NA You probably could do the same in aggregate, but I am not sure you can ... 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