{"id":12303,"date":"2022-09-30T09:35:31","date_gmt":"2022-09-30T04:05:31","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-pick-data-from-array-of-objects-and-return-new-object\/"},"modified":"2022-09-30T09:35:31","modified_gmt":"2022-09-30T04:05:31","slug":"solved-pick-data-from-array-of-objects-and-return-new-object","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-pick-data-from-array-of-objects-and-return-new-object\/","title":{"rendered":"[Solved] Pick data from array of objects and return new object"},"content":{"rendered":"

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This really is a simple one liner via map<\/code> and delete<\/code> or map<\/code> and ES6 destructuring<\/code> as shown in the 2 examples bellow:<\/p>\n<\/p>\n

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var data = [{\r\n    \"first\": \"Linda\",\r\n    \"last\": \"Donson\",\r\n    \"salary\": \"4000USD\"\r\n  },\r\n  {\r\n    \"first\": \"Mark\",\r\n    \"last\": \"Sullivan\",\r\n    \"salary\": \"3500USD\"\r\n  }\r\n]\r\n\r\nconsole.log(data.map(x => delete(x.salary) && x))<\/code><\/pre>\n<\/div>\n<\/div>\n
Also if you are concerned about mutating the object you can simply use ES6 destructuring<\/code> and the short object literal notation<\/code> to get this:<\/p>\n
Object.values(data).map(({first, last})  => ({first, last}))\n<\/code><\/pre>\n<\/p><\/div>\n
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            <\/span> <\/p><\/div>\n<\/div>\n
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solved Pick data from array of objects and return new object <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] This really is a simple one liner via map and delete or map and ES6 destructuring as shown in the 2 examples bellow: var data = [{ “first”: “Linda”, “last”: “Donson”, “salary”: “4000USD” }, { “first”: “Mark”, “last”: “Sullivan”, “salary”: “3500USD” } ] console.log(data.map(x => delete(x.salary) && x)) Also if you are concerned about … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[361,333,902,430],"class_list":["post-12303","post","type-post","status-publish","format-standard","hentry","category-solved","tag-arrays","tag-javascript","tag-node-js","tag-object"],"yoast_head":"\n[Solved] Pick data from array of objects and return new object - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-pick-data-from-array-of-objects-and-return-new-object\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Pick data from array of objects and return new object - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] This really is a simple one liner via map and delete or map and ES6 destructuring as shown in the 2 examples bellow: var data = [{ "first": "Linda", "last": "Donson", "salary": "4000USD" }, { "first": "Mark", "last": "Sullivan", "salary": "3500USD" } ] console.log(data.map(x => delete(x.salary) && x)) Also if you are concerned about ... 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