{"id":12069,"date":"2022-09-29T12:44:05","date_gmt":"2022-09-29T07:14:05","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-what-constitutes-a-stack-level-too-deep-error-code-kata\/"},"modified":"2022-09-29T12:44:05","modified_gmt":"2022-09-29T07:14:05","slug":"solved-what-constitutes-a-stack-level-too-deep-error-code-kata","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-what-constitutes-a-stack-level-too-deep-error-code-kata\/","title":{"rendered":"[Solved] What constitutes a stack level too deep error? Code Kata"},"content":{"rendered":"

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Your zeros<\/code> function is trying to do too much. It can’t calculate a factorial and at the same time count trailing zeroes in it.<\/p>\n

If you think about it, while you are calculating the factorial, number of trailing zeroes may (and will) change. You’re only interested in the final value. So first calculate that and only then count zeroes.<\/p>\n

# inefficient(!) recursive calculation of factorial\n# for more efficiency use loop\ndef factorial(n)\n  raise \"only positive values are allowed\" if n < 0\n\n  return 1 if n == 0\n  n * factorial(n - 1)\nend\n\ndef zeros(n)\n  trailing_zeros(factorial(n))\nend\n\ndef trailing_zeros(number)\n sort_sum = number.to_s.split(\/\/).reverse\n counter = 0\n until sort_sum[counter] != \"0\"\n  counter += 1\n end\n counter\nend\n\nzeros(5) # => 1\nzeros(12) # => 2\n<\/code><\/pre>\n<\/p><\/div>\n
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            6<\/span> <\/p><\/div>\n<\/div>\n
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solved What constitutes a stack level too deep error? Code Kata <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] Your zeros function is trying to do too much. It can’t calculate a factorial and at the same time count trailing zeroes in it. If you think about it, while you are calculating the factorial, number of trailing zeroes may (and will) change. You’re only interested in the final value. So first calculate that … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[455],"class_list":["post-12069","post","type-post","status-publish","format-standard","hentry","category-solved","tag-ruby"],"yoast_head":"\n[Solved] What constitutes a stack level too deep error? Code Kata - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-what-constitutes-a-stack-level-too-deep-error-code-kata\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] What constitutes a stack level too deep error? Code Kata - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Your zeros function is trying to do too much. It can’t calculate a factorial and at the same time count trailing zeroes in it. If you think about it, while you are calculating the factorial, number of trailing zeroes may (and will) change. You’re only interested in the final value. So first calculate that ... 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