{"id":10780,"date":"2022-09-24T23:25:41","date_gmt":"2022-09-24T17:55:41","guid":{"rendered":"http:\/\/jassweb.com\/solved\/solved-custom-hierarchy\/"},"modified":"2022-09-24T23:25:41","modified_gmt":"2022-09-24T17:55:41","slug":"solved-custom-hierarchy","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-custom-hierarchy\/","title":{"rendered":"[Solved] Custom hierarchy"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-72087435\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"72087435\" data-parentid=\"72086502\" data-score=\"2\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Here is a generic method regardless of the level of the hierarchy.<\/p>\n<p><strong>SQL<\/strong><\/p>\n<pre><code>-- DDL and sample data population, start\nDECLARE @tbl table (\n    idGeo INT IDENTITY PRIMARY KEY,\n    GEO   VARCHAR(64),\n    PARENTID INT\n);\n\ninsert into @tbl (GEO, PARENTID) values \n(   'EMEA',    NULL),\n(   'France',  1),\n(   'mIDCAPSfRANCE',   2),\n(   'Germany', 1),\n(   'France exl midcaps',  2),\n(   'Amercias',    NULL),\n(   'US',  6);\n-- DDL and sample data population, end\n\n--SELECT * FROM @tbl;\n\nWITH cte AS \n(\n    -- Anchor query\n    SELECT idGEO, GEO, ParentID, 1 AS [Level]\n        , CAST(\"https:\/\/stackoverflow.com\/\" + GEO AS VARCHAR(1000)) AS XPath\n    FROM @tbl\n    WHERE ParentID IS NULL\n    UNION ALL\n    -- Recursive query\n    SELECT t.idGEO, t.GEO, t.ParentID, cte.[Level] + 1 AS [Level]\n        , CAST(cte.[XPath] + \"https:\/\/stackoverflow.com\/\" +  t.GEO AS VARCHAR(1000)) AS [XPath]\n    FROM @tbl AS t\n        INNER JOIN cte ON t.ParentID = cte.idGEO\n    WHERE t.ParentID IS NOT NULL \n)\nSELECT idGEO\n    , REPLICATE('  ',[Level]-1) + GEO AS GEOHierarchy\n    , GEO, ParentID, [Level], [XPath]\nFROM cte\nORDER BY XPath;\n<\/code><\/pre>\n<p><strong>Output<\/strong><br \/>\n<a rel=\"nofollow noopener\" target=\"_blank\" href=\"http:\/\/jassweb.com\/solved\/wp-content\/uploads\/2022\/09\/Solved-Custom-hierarchy.png\"><img decoding=\"async\" src=\"http:\/\/jassweb.com\/solved\/wp-content\/uploads\/2022\/09\/Solved-Custom-hierarchy.png\" alt=\"enter image description here\"><\/a><\/p>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\"><\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved Custom hierarchy <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Here is a generic method regardless of the level of the hierarchy. SQL &#8212; DDL and sample data population, start DECLARE @tbl table ( idGeo INT IDENTITY PRIMARY KEY, GEO VARCHAR(64), PARENTID INT ); insert into @tbl (GEO, PARENTID) values ( &#8216;EMEA&#8217;, NULL), ( &#8216;France&#8217;, 1), ( &#8216;mIDCAPSfRANCE&#8217;, 2), ( &#8216;Germany&#8217;, 1), ( &#8216;France &#8230; <a title=\"[Solved] Custom hierarchy\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-custom-hierarchy\/\" aria-label=\"More on [Solved] Custom hierarchy\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[341,500,1009],"class_list":["post-10780","post","type-post","status-publish","format-standard","hentry","category-solved","tag-sql","tag-sql-server","tag-tsql"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] Custom hierarchy - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-custom-hierarchy\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Custom hierarchy - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Here is a generic method regardless of the level of the hierarchy. SQL -- DDL and sample data population, start DECLARE @tbl table ( idGeo INT IDENTITY PRIMARY KEY, GEO VARCHAR(64), PARENTID INT ); insert into @tbl (GEO, PARENTID) values ( &#039;EMEA&#039;, NULL), ( &#039;France&#039;, 1), ( &#039;mIDCAPSfRANCE&#039;, 2), ( &#039;Germany&#039;, 1), ( &#039;France ... 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SQL -- DDL and sample data population, start DECLARE @tbl table ( idGeo INT IDENTITY PRIMARY KEY, GEO VARCHAR(64), PARENTID INT ); insert into @tbl (GEO, PARENTID) values ( 'EMEA', NULL), ( 'France', 1), ( 'mIDCAPSfRANCE', 2), ( 'Germany', 1), ( 'France ... 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