{"id":10763,"date":"2022-09-24T22:16:27","date_gmt":"2022-09-24T16:46:27","guid":{"rendered":"http:\/\/jassweb.com\/solved\/solved-vectors-using-c\/"},"modified":"2022-09-24T22:16:27","modified_gmt":"2022-09-24T16:46:27","slug":"solved-vectors-using-c","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-vectors-using-c\/","title":{"rendered":"[Solved] Vectors using C++"},"content":{"rendered":"

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why here vector <int> :: iterator i;<\/code><\/p>\n<\/blockquote>\n

The vector <int> :: iterator i;<\/code> is created in order to traverse the vector vector <int> g1;<\/code> (actually it can traverse any vector<int><\/code>, but in this case, that’s for g1<\/code>)<\/p>\n

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is there a difference between vector <int> :: iterator i<\/code>; and int i<\/code>?<\/p>\n<\/blockquote>\n

The scope of vector <int> :: iterator i;<\/code> is the main<\/code> function. Inside main<\/code>, a new scope is created:<\/p>\n

for (int i = 1; i <= 5; i++)\n        g1.push_back(i);\n<\/code><\/pre>\n
In that scope, i<\/code> is the int<\/code> defined in the loop start, but it dies at the end of the loop, and after that i<\/code> “returns to be” the vector <int> :: iterator i<\/code><\/p>\n
int main()\n{\n    vector <int> g1;\n    vector <int> :: iterator i;           \/\/ i is the iterator\n    vector <int> :: reverse_iterator ir;\n\n    for (int i = 1; i <= 5; i++)         \/\/ here i the int\n        g1.push_back(i);                 \/\/ also here\n                                         \/\/ from here the int i is dead, and i is back to being an iterator\n    cout << \"Output of begin and end\\t:\\t\";\n    for (i = g1.begin(); i != g1.end(); ++i)  \n        cout << *i << '\\t';\n\n    cout << endl << endl;\n    cout << \"Output of rbegin and rend\\t:\\t\";\n    for (ir = g1.rbegin(); ir != g1.rend(); ++ir)\n        cout << '\\t' << *ir;\n\n    return 0;\n\n}\n<\/code><\/pre>\n<\/p><\/div>\n
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solved Vectors using C++ <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] why here vector <int> :: iterator i; The vector <int> :: iterator i; is created in order to traverse the vector vector <int> g1; (actually it can traverse any vector<int>, but in this case, that’s for g1) is there a difference between vector <int> :: iterator i; and int i? The scope of vector … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[324,806],"class_list":["post-10763","post","type-post","status-publish","format-standard","hentry","category-solved","tag-c","tag-vector"],"yoast_head":"\n[Solved] Vectors using C++ - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-vectors-using-c\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] Vectors using C++ - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] why here vector <int> :: iterator i; The vector <int> :: iterator i; is created in order to traverse the vector vector <int> g1; (actually it can traverse any vector<int>, but in this case, that’s for g1) is there a difference between vector <int> :: iterator i; and int i? The scope of vector ... 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