{"id":10444,"date":"2022-09-23T18:01:51","date_gmt":"2022-09-23T12:31:51","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-find-latest-entry-for-each-group-and-display-in-a-separate-sheet-in-excel\/"},"modified":"2022-09-23T18:01:51","modified_gmt":"2022-09-23T12:31:51","slug":"solved-how-to-find-latest-entry-for-each-group-and-display-in-a-separate-sheet-in-excel","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-find-latest-entry-for-each-group-and-display-in-a-separate-sheet-in-excel\/","title":{"rendered":"[Solved] How to find latest entry for each group and display in a separate sheet in Excel"},"content":{"rendered":"<p> [ad_1]<br \/>\n<\/p>\n<div id=\"answer-51468329\" class=\"answer js-answer accepted-answer js-accepted-answer\" data-answerid=\"51468329\" data-parentid=\"51467885\" data-score=\"2\" data-position-on-page=\"1\" data-highest-scored=\"1\" data-question-has-accepted-highest-score=\"1\" itemprop=\"acceptedAnswer\" itemscope itemtype=\"https:\/\/schema.org\/Answer\">\n<div class=\"post-layout\">\n<div class=\"votecell post-layout--left\"><\/div>\n<div class=\"answercell post-layout--right\">\n<div class=\"s-prose js-post-body\" itemprop=\"text\">\n<p>Here is one way using arrays. Depending on the size of your data you may hit a limit with Transpose, in which case I can re-write part of the solution.<\/p>\n<p>I have used &#8220;,&#8221; delimiter to keep track of separate column items when concatenating together.You may wish to swop this with a symbol you do not expect to find in your data to ensure you do not end up with unexpected results.<br \/>\nChange the value here,  <code>Const DELIMITER As String = \",\"<\/code> , if changing the delimiter.<\/p>\n<pre><code>Option Explicit\nPublic Sub GetLastDateInfo()\n    Application.ScreenUpdating = False\n    Const DELIMITER As String = \",\"\n    Dim arr(), resultsArr(), dict As Object, i As Long, currDate As Long, ws As Worksheet, headers()\n    headers = Array(\"Entry Date\", \"Project Date\", \"Project ID\", \"Status\")\n    Set ws = ThisWorkbook.Worksheets(\"Sheet1\"): Set dict = CreateObject(\"Scripting.Dictionary\")\n    arr = ws.Range(\"A2:D\" &amp; GetLastRow(ws, 1)).Value\n    ReDim resultsArr(1 To UBound(arr, 1), 1 To UBound(arr, 2))\n\n    For i = LBound(arr, 1) To UBound(arr, 1)\n        currDate = CLng(CDate(Replace$(arr(i, 1), \".\", \"-\")))\n        If Not dict.Exists(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)) Then\n            dict.Add arr(i, 2) &amp; DELIMITER &amp; arr(i, 3), currDate &amp; DELIMITER &amp; arr(i, 4)\n        ElseIf Split(dict(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)), DELIMITER)(0) &lt; currDate Then\n            dict(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)) = currDate &amp; DELIMITER &amp; arr(i, 4)\n        End If\n    Next i\n    Dim key As Variant, r As Long, tempArr() As String\n    For Each key In dict.keys\n        r = r + 1\n        tempArr = Split(dict(key), DELIMITER)\n        resultsArr(r, 1) = tempArr(0)\n        resultsArr(r, 4) = tempArr(1)\n        tempArr = Split(key, DELIMITER)\n        resultsArr(r, 2) = tempArr(0)\n        resultsArr(r, 3) = tempArr(1)\n    Next key\n    resultsArr = Application.WorksheetFunction.Transpose(resultsArr)\n    ReDim Preserve resultsArr(1 To UBound(resultsArr, 1), 1 To r)\n    resultsArr = Application.WorksheetFunction.Transpose(resultsArr)\n    With Worksheets(\"Sheet2\")\n        .Range(\"A1\").Resize(1, UBound(headers) + 1) = headers\n        .Range(\"A2\").Resize(UBound(resultsArr, 1), UBound(resultsArr, 2)) = resultsArr\n    End With\n    Application.ScreenUpdating = True\nEnd Sub\n\nPublic Function GetLastRow(ByVal ws As Worksheet, Optional ByVal columnNumber As Long = 1) As Long\n    With ws\n        GetLastRow = .Cells(.Rows.Count, columnNumber).End(xlUp).Row\n    End With\nEnd Function\n<\/code><\/pre>\n<hr>\n<p><strong>Output:<\/strong><\/p>\n<p><a rel=\"nofollow noopener\" target=\"_blank\" href=\"https:\/\/jassweb.com\/solved\/wp-content\/uploads\/2022\/09\/Solved-How-to-find-latest-entry-for-each-group-and.png\"><img decoding=\"async\" src=\"https:\/\/jassweb.com\/solved\/wp-content\/uploads\/2022\/09\/Solved-How-to-find-latest-entry-for-each-group-and.png\" alt=\"output\"><\/a><\/p>\n<hr>\n<p><strong>Adapted for increased number of columns ( uses GetLastRow function from above):<\/strong><\/p>\n<pre><code> Public Sub GetLastDateInfo2()\n    Application.ScreenUpdating = False\n    Const DELIMITER As String = \",\"\n    Dim arr(), resultsArr(), dict As Object, dict2 As Object, i As Long, j As Long\n    Dim currDate As Long, ws As Worksheet, headers()\n    Set ws = ThisWorkbook.Worksheets(\"Sheet1\")\n    headers = ws.Range(\"A1:AN1\").Value\n    headers = Application.WorksheetFunction.Index(headers, 1, 0)\n    Set dict = CreateObject(\"Scripting.Dictionary\"): Set dict2 = CreateObject(\"Scripting.Dictionary\")\n    arr = ws.Range(\"A2:AN\" &amp; GetLastRow(ws, 1)).Value\n    ReDim resultsArr(1 To UBound(arr, 1), 1 To UBound(arr, 2))\n\n    For i = LBound(arr, 1) To UBound(arr, 1)\n        currDate = CLng(CDate(Replace(arr(i, 1), \".\", \"-\")))\n        If Not dict.Exists(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)) Then\n            dict.Add arr(i, 2) &amp; DELIMITER &amp; arr(i, 3), currDate\n            dict2.Add arr(i, 2) &amp; DELIMITER &amp; arr(i, 3), arr(i, 4)\n            For j = 5 To UBound(arr, 2)\n                dict2(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)) = dict2(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)) &amp; DELIMITER &amp; arr(i, j)\n            Next j\n        ElseIf Split(dict(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)), DELIMITER)(0) &lt; currDate Then\n            dict(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)) = currDate\n            dict2(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)) = vbNullString\n            For j = 4 To UBound(arr, 2)\n                dict2(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)) = dict2(arr(i, 2) &amp; DELIMITER &amp; arr(i, 3)) &amp; DELIMITER &amp; arr(i, j)\n            Next j\n        End If\n    Next i\n    Dim key As Variant, r As Long, tempArr() As String\n\n    For Each key In dict.keys\n        r = r + 1\n        tempArr = Split(dict(key), DELIMITER)\n        resultsArr(r, 1) = tempArr(0)\n        tempArr = Split(key, DELIMITER)\n        resultsArr(r, 2) = tempArr(0)\n        resultsArr(r, 3) = tempArr(1)\n        resultsArr(r, 4) = Replace$(dict2(key), DELIMITER, vbNullString, , 1)\n    Next key\n    resultsArr = Application.WorksheetFunction.Transpose(resultsArr)\n    ReDim Preserve resultsArr(1 To UBound(resultsArr, 1), 1 To r)\n    resultsArr = Application.WorksheetFunction.Transpose(resultsArr)\n    Application.DisplayAlerts = False\n    With Worksheets(\"Sheet2\")\n         .UsedRange.ClearContents\n        .Range(\"A2\").Resize(UBound(resultsArr, 1), UBound(resultsArr, 2)) = resultsArr\n        .Columns(\"D\").TextToColumns Destination:=Range(\"D1\"), DataType:=xlDelimited, _\n        TextQualifier:=xlDoubleQuote,Other:=True, OtherChar _\n        :=DELIMITER, TrailingMinusNumbers:=True\n        .Range(\"A1\").Resize(1, UBound(headers)) = headers\n    End With\n    Application.DisplayAlerts = True\n    Application.ScreenUpdating = True\nEnd Sub\n<\/code><\/pre>\n<\/p><\/div>\n<div class=\"mt24\"><\/div>\n<\/div>\n<p>            <span class=\"d-none\" itemprop=\"commentCount\">9<\/span> <\/p><\/div>\n<\/div>\n<p>[ad_2]<\/p>\n<p>solved How to find latest entry for each group and display in a separate sheet in Excel <\/p>\n","protected":false},"excerpt":{"rendered":"<p>[ad_1] Here is one way using arrays. Depending on the size of your data you may hit a limit with Transpose, in which case I can re-write part of the solution. I have used &#8220;,&#8221; delimiter to keep track of separate column items when concatenating together.You may wish to swop this with a symbol you &#8230; <a title=\"[Solved] How to find latest entry for each group and display in a separate sheet in Excel\" class=\"read-more\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-find-latest-entry-for-each-group-and-display-in-a-separate-sheet-in-excel\/\" aria-label=\"More on [Solved] How to find latest entry for each group and display in a separate sheet in Excel\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[400,401],"class_list":["post-10444","post","type-post","status-publish","format-standard","hentry","category-solved","tag-excel","tag-vba"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>[Solved] How to find latest entry for each group and display in a separate sheet in Excel - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-find-latest-entry-for-each-group-and-display-in-a-separate-sheet-in-excel\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] How to find latest entry for each group and display in a separate sheet in Excel - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] Here is one way using arrays. Depending on the size of your data you may hit a limit with Transpose, in which case I can re-write part of the solution. I have used &#8220;,&#8221; delimiter to keep track of separate column items when concatenating together.You may wish to swop this with a symbol you ... 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Depending on the size of your data you may hit a limit with Transpose, in which case I can re-write part of the solution. I have used &#8220;,&#8221; delimiter to keep track of separate column items when concatenating together.You may wish to swop this with a symbol you ... 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