{"id":10259,"date":"2022-09-23T01:25:01","date_gmt":"2022-09-22T19:55:01","guid":{"rendered":"https:\/\/jassweb.com\/solved\/solved-how-to-change-the-particuler-elements-of-an-array\/"},"modified":"2022-09-23T01:25:01","modified_gmt":"2022-09-22T19:55:01","slug":"solved-how-to-change-the-particuler-elements-of-an-array","status":"publish","type":"post","link":"https:\/\/jassweb.com\/solved\/solved-how-to-change-the-particuler-elements-of-an-array\/","title":{"rendered":"[Solved] how to change the particuler elements of an array"},"content":{"rendered":"

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You can use a 2D convolution on the 1s with a 3×3 kernel of 1s to identify the centers of the 3×3 squares, then dilate them and restore the non 1 numbers<\/p>\n

from scipy.signal import convolve2d\nfrom scipy.ndimage import binary_dilation\n\n# get 1s (as boolean)\nm = data==1\n\nkernel = np.ones((3, 3))\n\n# get centers\nconv = convolve2d(m, kernel, mode=\"same\")\n\n# dilate and restore the other numbers\nout = np.where(m, binary_dilation(conv == 9, kernel).astype(int), data)\n\nprint(out)\n<\/code><\/pre>\n
Alternative, erosion and dilation, similarly to my previous answer:<\/p>\n
from scipy.ndimage import binary_dilation, binary_erosion\n\nm = data==1\nkernel = np.ones((3, 3))\n\nout = np.where(m, binary_dilation(binary_erosion(m, kernel), kernel), data)\n<\/code><\/pre>\n
Output:<\/p>\n
[[4 4 4 0 1 1 1 1 1 1 0 0 0 0 0]\n [3 0 0 0 1 1 1 1 1 1 1 1 1 0 0]\n [6 0 0 0 1 1 1 1 1 1 1 1 1 0 0]\n [2 0 0 0 1 1 1 0 0 0 1 1 1 0 0]\n [2 0 0 0 1 1 1 0 0 0 0 0 0 0 0]]\n<\/code><\/pre>\n<\/p><\/div>\n
<\/div>\n<\/div>\n
            1<\/span> <\/p><\/div>\n<\/div>\n
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solved how to change the particuler elements of an array <\/p>\n","protected":false},"excerpt":{"rendered":"
[ad_1] You can use a 2D convolution on the 1s with a 3×3 kernel of 1s to identify the centers of the 3×3 squares, then dilate them and restore the non 1 numbers from scipy.signal import convolve2d from scipy.ndimage import binary_dilation # get 1s (as boolean) m = data==1 kernel = np.ones((3, 3)) # get … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[320],"tags":[581,349,2825,792],"class_list":["post-10259","post","type-post","status-publish","format-standard","hentry","category-solved","tag-numpy","tag-python","tag-scikit-image","tag-scikit-learn"],"yoast_head":"\n[Solved] how to change the particuler elements of an array - JassWeb<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/jassweb.com\/solved\/solved-how-to-change-the-particuler-elements-of-an-array\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"[Solved] how to change the particuler elements of an array - JassWeb\" \/>\n<meta property=\"og:description\" content=\"[ad_1] You can use a 2D convolution on the 1s with a 3×3 kernel of 1s to identify the centers of the 3×3 squares, then dilate them and restore the non 1 numbers from scipy.signal import convolve2d from scipy.ndimage import binary_dilation # get 1s (as boolean) m = data==1 kernel = np.ones((3, 3)) # get ... 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