{"version":"1.0","provider_name":"JassWeb","provider_url":"https:\/\/jassweb.com\/solved","author_name":"Kirat","author_url":"https:\/\/jassweb.com\/solved\/author\/jaspritsinghghumangmail-com\/","title":"[Solved] Taking derivative of a function - JassWeb","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"hrJbwQ1kQ9\"><a href=\"https:\/\/jassweb.com\/solved\/solved-taking-derivative-of-a-function\/\">[Solved] Taking derivative of a function<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/jassweb.com\/solved\/solved-taking-derivative-of-a-function\/embed\/#?secret=hrJbwQ1kQ9\" width=\"600\" height=\"338\" title=\"&#8220;[Solved] Taking derivative of a function&#8221; &#8212; JassWeb\" data-secret=\"hrJbwQ1kQ9\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/jassweb.com\/solved\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"[ad_1] Let F(p,q) be F(p,q) = sum(j, [ r(j) - sum(i, p(i,j)*q(i,j)) ]^2 ) Then dF\/dp is the matrix A formed by elements A(i,j) = 2 * [r(j) - sum(k, p(k,j)*q(k,j))] * (-q(i,j)) dF\/dq is the matrix B formed by elements B(i,j) = 2 * [r(j) - sum(k, p(k,j)*q(k,j))] * (-p(i,j)) 2 [ad_2] solved Taking ... Read more"}