{"version":"1.0","provider_name":"JassWeb","provider_url":"https:\/\/jassweb.com\/solved","author_name":"Kirat","author_url":"https:\/\/jassweb.com\/solved\/author\/jaspritsinghghumangmail-com\/","title":"[Solved] Split Array By Values In Sequence [duplicate] - JassWeb","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"uNHPYlZRuA\"><a href=\"https:\/\/jassweb.com\/solved\/solved-split-array-by-values-in-sequence-duplicate\/\">[Solved] Split Array By Values In Sequence [duplicate]<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/jassweb.com\/solved\/solved-split-array-by-values-in-sequence-duplicate\/embed\/#?secret=uNHPYlZRuA\" width=\"600\" height=\"338\" title=\"&#8220;[Solved] Split Array By Values In Sequence [duplicate]&#8221; &#8212; JassWeb\" data-secret=\"uNHPYlZRuA\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/jassweb.com\/solved\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"[ad_1] This can work with the linq extension Aggregate. My seeding is not very elegant but that is easy enough to change. The results variable will contain the array of arrays and they are actually of type List&lt;T&gt; because that way they can be easily grown in the function where an array [] is always ... Read more"}