{"version":"1.0","provider_name":"JassWeb","provider_url":"https:\/\/jassweb.com\/solved","author_name":"Kirat","author_url":"https:\/\/jassweb.com\/solved\/author\/jaspritsinghghumangmail-com\/","title":"[Solved] Group duplicate items in vector - c++ [closed] - JassWeb","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"rjE5zqPKCK\"><a href=\"https:\/\/jassweb.com\/solved\/solved-group-duplicate-items-in-vector-c-closed\/\">[Solved] Group duplicate items in vector &#8211; c++ [closed]<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/jassweb.com\/solved\/solved-group-duplicate-items-in-vector-c-closed\/embed\/#?secret=rjE5zqPKCK\" width=\"600\" height=\"338\" title=\"&#8220;[Solved] Group duplicate items in vector &#8211; c++ [closed]&#8221; &#8212; JassWeb\" data-secret=\"rjE5zqPKCK\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/jassweb.com\/solved\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"[ad_1] You&#8217;re close. You already figured out your bounds problem, but consider what happens at the interface of clusters: ..2,2,3,3... ^ ^ i i+1 You are going to enter the else (else if is unnecessary if the condition is the exact opposite of the original if) and forget to add that last 2. If there ... Read more"}