1.0JassWebhttps://jassweb.com/solvedKirathttps://jassweb.com/solved/author/jaspritsinghghumangmail-com/rich600338<blockquote class="wp-embedded-content" data-secret="O1tiYcPdIU"><a href="https://jassweb.com/solved/solved-prolog-define-predicates-closed/">[Solved] Prolog Define Predicates [closed]</a></blockquote><iframe sandbox="allow-scripts" security="restricted" src="https://jassweb.com/solved/solved-prolog-define-predicates-closed/embed/#?secret=O1tiYcPdIU" width="600" height="338" title="“[Solved] Prolog Define Predicates [closed]” — JassWeb" data-secret="O1tiYcPdIU" frameborder="0" marginwidth="0" marginheight="0" scrolling="no" class="wp-embedded-content"></iframe><script> /*! This file is auto-generated */ !function(d,l){"use strict";l.querySelector&&d.addEventListener&&"undefined"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!/[^a-zA-Z0-9]/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret="'+t.secret+'"]'),o=l.querySelectorAll('blockquote[data-secret="'+t.secret+'"]'),c=new RegExp("^https?:$","i"),i=0;i<o.length;i++)o[i].style.display="none";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute("style"),"height"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):"link"===t.message&&(r=new URL(s.getAttribute("src")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener("message",d.wp.receiveEmbedMessage,!1),l.addEventListener("DOMContentLoaded",function(){for(var e,t,s=l.querySelectorAll("iframe.wp-embedded-content"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute("data-secret"))||(t=Math.random().toString(36).substring(2,12),e.src+="#?secret="+t,e.setAttribute("data-secret",t)),e.contentWindow.postMessage({message:"ready",secret:t},"*")},!1)))}(window,document); //# sourceURL=https://jassweb.com/solved/wp-includes/js/wp-embed.min.js </script> [ad_1] Try this one 🙂 The main idea is to accumulate number of hours in the predicate min by subtracting 60 from total time and when the total time is lower than 60 we can unify counted hours from accumulator with H variable and rest of time with M variable. minutes(X,H,M):- %main predicate min(X,0,H,M). min(X,H,ResultH,ResultM):- ... Read more