Your English segments are located in the first column. All you need to do is English = [sent.split(‘\t’)[0] for sent in data_examples] 0 solved Extracting all text before first tab from a list of strings
The data is fixed width columns so use following : using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.IO; using System.Data; namespace ConsoleApplication1 { class Program { const string FILENAME = @”c:\temp\test.txt”; static void Main(string[] args) { FIX_WIDTH fixWidth = new FIX_WIDTH(FILENAME); } } public class FIX_WIDTH { int[] Start_Position = { 0, 55, … Read more
That’s not a list. You are using a dictionary with key and value. Get the value, split on comma and find length using len. workdays = {‘work’: ‘5,6,8,10,13,14,15,18,20,22,24,25,28,30’} print(‘I have worked {} days’.format(len(workdays[‘work’].split(‘,’)))) Also, you could count the number of commas and add 1 to it to get the same result like so: print(‘I have … Read more
Looking at your input and expected output there is a space that has gone missing. If you really want to remove that space you could use LINQs Select extension method: var orderElements = order.Split(‘\”).Select(s => s.Trim()).ToList(); Also the string ends in an ‘ so you might want to remove empty entries like: .Split(new char[] { … Read more
Use a wordwrap function: <? $text = “kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk”; $newtext = wordwrap($text, 20, “<br />\n”); ?> 1 solved String to get string to second line? [duplicate]
Here is what worked for me – using inputs from above and various other threads on SO. I am a complete newbie to R and my objective is to migrate work from excel to R. # returns string w/o leading or trailing whitespace trim <- function (x) gsub(“^\\s+|\\s+$”, “”, x) #——————————————————————————– # OBJECTIVE – migrate … Read more
You can use re module for the task: style=”fill: rgb(0, 0, 0); fill-opacity: 1; font-family: ProjectStocksFont; font-size: 70px; font-weight: normal; font-style: normal; text-decoration: none;” import re print( re.search(r’font-size:\s*(\d+)’, style)[1] ) Prints: 70 3 solved Python get info from long complicated string
some how I achieved it in lengthy way …Not sure if any shortcut is there to achieve… var keywords_updated = (keywords.Replace(” “, “* “)); keywords_updated = keywords_updated.EndsWith(““) ? keywords_updated : keywords_updated + ““; MatchCollection col = Regex.Matches(keywords, “\\”(.?)\\””);//Regex.Matches(keywords, “(?<=\”)[^\”](?=\”)|[^\” ]+”); var data = col.Cast().Select(m => m.Value).ToList(); Console.WriteLine(data.Count); foreach (var item in data) { keywords_updated = … Read more
This uses STRING_AGG to aggregate the strings into one long one, and then a Tally Table to split into the new rows. It is assumed you have a column to order by. if you do not, you cannot achieve what you are after without one as data in a table is stored in an unordered … Read more
I figured it out. string = ‘123456789’ splitted = [] prev = 0 while True: n = random.randint(1,3) splitted.append(string[prev:prev+n]) prev = prev + n if prev >= len(string)-1: break print splitted 0 solved Split string by n when n is random