[Solved] Python re: how to lowercase some words [closed]

Wanted solution using regex, here you are: >>> import re >>> s = “StringText someText Wwwwww SomeOtherText OtherText SOMETextMore etc etc etc” >>> def replacement(match): … return match.group(1).lower() >>> re.sub(r'([sS]\w+)’, replacement, s) ‘stringtext sometext Wwwwww someothertext OtherText sometextmore etc etc etc’ 10 solved Python re: how to lowercase some words [closed]

[Solved] Inserting and removing a character from a string

Adding characters “customer” <> “s” Removing characters Elixir idiomatic: String.trim_trailing(“users”, “s”) #⇒ “user” More efficient for long strings: with [_ | tail] <- “users” |> to_charlist |> :lists.reverse, do: tail |> :lists.reverse |> to_string Most efficient (credits to @Dogbert): str = “users” sz = :erlang.byte_size(str), :erlang.binary_part(str, {0, sz – 1}) 6 solved Inserting and removing a … Read more

[Solved] Need Regular Expression for Format -xx-xxx-x- [closed]

<?php $url = “http://<hostname>/p/Brand-Product-Name-6118-161-1-gallery.jpg”; preg_match_all(‘#(\d+)-(\d+)-\d+-gallery\.jpg$#’,$url,$matches); // Depends on how accurate you want to be. You can go with many choices like: // preg_match_all(‘#http\://.*?/p/.*?(\d+)-(\d+)-\d+-.*\.jpg#’,$url,$matches); var_dump($matches); /* array(3) { [0]=> array(1) { [0]=> string(22) “6118-161-1-gallery.jpg” } [1]=> array(1) { [0]=> string(4) “6118” } [2]=> array(1) { [0]=> string(3) “161” } } */ 1 solved Need Regular Expression … Read more

[Solved] Regular expression in python string [closed]

This works: import re s=””‘customer is given as per below customer are given not priority below given given below customer below customer information given customer is given not as per below”’ matches = re.findall(‘customer \S+ given \S+\s\S+ below’, s) for match in matches: print(match) 14 solved Regular expression in python string [closed]

[Solved] How to print a work in string containing specific characters [closed]

You could use the following regular expression: import re text = “fieldnameRelated_actions/fieldnamedatatypeRESOURCE_LIST![CDATA[nprod00123456]/value>value>![CDATA[nprod00765432]]/valuevaluesfield” print re.findall(r'(nprod\d+)’, text) Giving you: [‘nprod00123456’, ‘nprod00765432’] This works by finding any nprod in the text followed by one or more digits. Alternatively, without re, it might be possible as follows: print [‘nprod{}’.format(t.split(‘]’)[0]) for t in text.split(‘nprod’)[1:]] 1 solved How to print a … Read more

[Solved] Looking for regex solution [closed]

Will be [0-9]{2}\.[0-9]{2}\.[0-9]{4} [0-9]stands for any integer in range 0 to 9, the number in curly brackets ({2} in this case) indicates how many times should the pattern be repeated. You need to escape the dots with a backslash because otherwise they will be interpreted as any character. 0 solved Looking for regex solution [closed]