Try this
DECLARE @temp TABLE(col1 varchar(20),col2 int, col3 varchar(20))
insert into @temp values ('data1', 123 , '12/03/2009'),('data1', 124 , '15/09/2009'),
('data2 ',333 ,'02/09/2010'),('data2 ',323 , '02/11/2010'),
('data2 ',673 , '02/09/2014'),('data2',444 , '05/01/2010')
SELECT
(CASE rno WHEN 1 THEN col1 ELSE '' END )AS col1,
col2,
col3
FROM
(
SELECT
ROW_NUMBER() OVER(PARTITION BY Col1 ORDER BY col2) AS rno,
col1,col2,col3
FROM @temp
) As temp
This gives the following output
col1 col2 col3
---------------------------------
data1 123 12/03/2009
124 15/09/2009
data2 323 02/11/2010
333 02/09/2010
444 05/01/2010
673 02/09/2014
PARTITION BY
is grouping the data with the given column name, and a row number is generated in that group based on the order by
.
Here is the SQL Fiddle
I have created another fiddle based on the schema provided .fiddle2
12
solved How to group rows with same value in sql? [closed]