Your problem comes from a bad use of switch/case. See Switch/Case documentation. Your menu switch/case will triggered every cases switch(1) { case 1 : cout << ‘1’; // prints “1”, case 2 : cout << ‘2’; // then prints “2” } and switch(1) { case 1 : cout << ‘1’; // prints “1” break; // … Read more
I figured it out. string = ‘123456789’ splitted = [] prev = 0 while True: n = random.randint(1,3) splitted.append(string[prev:prev+n]) prev = prev + n if prev >= len(string)-1: break print splitted 0 solved Split string by n when n is random
Try the regular expression ^\\d{10,15}$ Here \d is a predefined character class for digits{10, 15} quantifier stands for a repeat of 10 to 15 times of the previous pattern Ex: String input = “1234567890”; Pattern pattern = Pattern.compile(“^\\d{10,15}$”); if (pattern.matcher(input).find()) { System.out.println(“Valid”); } 0 solved Phone number validation regex for length and numeric values [duplicate]
If you have char arr[10] = “1234567890” as per your question, note that it is not a string since it has no room for the NUL terminator (would need size 11, or left empty [] for the compiler to count for you). Assuming you want two strings out of it, you need to copy the … Read more
To format a number using fixed-point notation, you can simply use the toFixed method: (10.8).toFixed(2); // “10.80” var num = 2.4; alert(num.toFixed(2)); // “2.40” Note that toFixed() returns a string. IMPORTANT: Note that toFixed does not round 90% of the time, it will return the rounded value, but for many cases, it doesn’t work. For … Read more
This looks a bit like minimised code, where function call are often shortened by creating lookup tables, so you can save some bits on long function calls like Element.dispatchEvent and instead minimise it to e[l(p)]. The variable _0x76ed32 holds the reference to your input element. _0x76ed32[‘dispatchEvent’](new Event(‘blur’)) This is a function call on your element. … Read more
In your html view page some change echo “<td><a href=”https://stackoverflow.com/questions/40479421/delete.php?did=”.$row[“id’].”‘>Delete</a></td>”; like bellow: <?php while($row = mysql_fetch_array($result)) { echo “<tr>”; echo “<td>” . $row[‘name’] . “</td>”; echo “<td>” . $row[‘id’] . “</td>”; echo “<td>” . $row[‘rollnumber’] . “</td>”; echo “<td>” . $row[‘address’] . “</td>”; echo “<td>” . $row[‘phonenumber’] . “</td>”; echo “<td><a href=”https://stackoverflow.com/questions/40479421/delete.php?did=”.$row[“id’].”‘>Delete</a></td>”; echo “</tr>”; } … Read more
Looking at your code you are trying to print the element itself. System.out.println(FatherNum); If you want to print the value of that field , you can do it by : System.out.println(FatherNum.getAttribute(“value”)); OR String Fathernum= FatherNum.getAttribute(“value”); System.out.println(Fathernum); See the doc for getAttribute – see link 1 solved How to retrieve integer value from field in selenium?
Fairly simple: use two loops, one for counting up and one for counting down. Print literal “0” between the two. #include <stdio.h> int main() { for (int i = 0; i < 10; i++) { for (int j = 10 – i; j < 10; j++) printf(“%d”, j); printf(“0”); for (int j = 9; j … Read more
The order is wrong. out is an object of arrays (not an array of objects). Here I fixed the order of access with the assumption, that all properties contain an array with the same length: function fetch() { return Promise.resolve({ json() { return Promise.resolve({ “name”: [ “John”, “Marie”, “Clara” ], “surname”: [ “Doe”, “Jane”, “Smith” … Read more